So first simplify 11/6x into 11x/6. Then -13/10x into -13x/10. So you should now have (-13x/10-11x/4)-3/2. Combine the like terms -13x/10 and -11x/4 to get -81x/20 and then with your left over -3/2= -81x/20-3/2
Answer:
no it to low
Step-by-step explanation:
the answer was 4998
Answer:
x = 10°
Step-by-step explanation:
a). Since, opposite angles of a cyclic quadrilateral are supplementary angles"
Therefore, in cyclic quadrilateral ABDE,
m∠ABD + m∠AED = 180°
110° + m∠AED = 180°
m∠AED = 180° - 110°
= 70°
b). AD = ED [Given]
m∠EAD = m∠AED [Since, opposite angles of equal sides are equal in measure]
m∠EAD = m∠AED = 70°
By triangle sum theorem in ΔABD,
m∠BAD + m∠ABD + m∠ADB = 180°
m∠BAD + 110° + 40° = 180°
m∠BAD = 180 - 150
= 30°
m∠AEB = m∠AED + m∠DAB [By angles addition postulate]
m∠AEB = 70° + 30°
= 100°
By triangle sum theorem in the large triangle,
x° + m∠AEB + m∠EAB = 180°
x° + 100° + 70° = 180°
x = 180 - 170
x = 10°
The answer to the question is c
Answer:
f(2) = 0
Step-by-step explanation:
Function f(t) is defined in three different ways depending on the value of t.
For t = 8, function f(t) is -64/t.
For t = 10, function f(t) is 14 - t.
We are not asked about f(8) or f(10). We are asked about f(2). The third definition of function f(t) is for all values of t that are not 8 or 10. 2 is not 8 or 10, so use the third definition of function f(t) and plug in 2 for t.
f(t) = t^2 - 3t + 2 for t not equal to 8 or 10.
f(2) = 2^2 - 3(2) + 2
f(2) = 4 - 6 + 2
f(2) = 0
