The outermost structure that surrounds and supports plant and fungal cells should be A. Cell wall.
Periods are subdivided into eras by geologists.
The mass in grams of nitric acid that is required to react with 454g C7H8 is 932.72 grams
calculation
find the moles of C7H8 used
moles = mass/molar mass
= 454 g/92 = 4.935 moles
balanced reacting equation
C7H8 +3 HNO3 = C7H5N3O6 +3 H20
by use of mole ratio between C7H8 to HNo3 which is 1:3 the moles of HNO3 =4.935 x3 = 14.805 moles
mass of HNo3 = moles x molar mass
= 14.805 x 63 = 932.72 grams
part B
the mass of C7H5N3o6 = 2045.5 grams
calculate the moles of C7H8
= 829 g/92 g/mol = 9.011 moles
by use of mole ratio between C7H8 to C7H5N3O6 which is 1:1 the moles of C7H5N3O6 is also = 9.011 moles
mass of C7H5N3O6 is therefore = moles x molar mass
=9.011 x227 = 2045.5 grams
Answer:
Explanation:
Given data:
A) Moles of H₂O₂ = 7.00
Mass of H₂O₂ = ?
Solution:
Number of moles = mass/ molar mass
Now we will rearrange this formula:
Mass = Number of moles × molar mass
Mass = 7.00 mol × 34 g/mol
Mass = 238 g
B) Moles of NaOH = 5.60 mol
Mass of NaOH = ?
Solution:
Number of moles = mass/ molar mass
Now we will rearrange this formula:
Mass = Number of moles × molar mass
Mass = 5.60 mol × 40 g/mol
Mass = 224 g
C) Moles of Ca(CN)₂ = 0.780
Mass of Ca(CN)₂ = ?
Solution:
Number of moles = mass/ molar mass
Now we will rearrange this formula:
Mass = Number of moles × molar mass
Mass = 0.780 mol × 92.11 g/mol
Mass = 71.85 g
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