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Tanya [424]
2 years ago
5

Calculate the number of moles of each compound, given the number of molecules.

Chemistry
1 answer:
brilliants [131]2 years ago
5 0

Answer:

1.  2.46\times 10^{21} molecules of CO₂

2. 10⁴ molecules of H₂O

3. 8.75×10³² molecules of C₆H₁₂O₆

Explanation:

1.  2.46\times 10^{21} molecules of CO₂

2. 10⁴ molecules of H₂O

3. 8.75×10³² molecules of C₆H₁₂O₆

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I need help with problem 103 all of the questions.
AfilCa [17]
A. is decomposition so HCL = H2 + Cl2

not balanced cause hcl needs 2

2HCL = H2 + Cl2

balanced

b. Br2 + Al-i = AlBr3 + I2 single rep.

not balanced since br need 3 so watch carefully cause many changes needed


 3Br2 + Al-i = AlBr3 + I2 not right is unbalanced so make it 2

3Br2 + Al-i = 2AlBr3 + I2 now left Al is unbal. so make 2 there

3Br2 + 2Ali = 2AlBr3 + I2 

Balanced

C. Na + S = Na2S synthesis reaction is not bal. left Na needs 2

2Na + S = Na2S  balanced.

4 0
2 years ago
Find the density of an object that has a mass of 5 kg and a volume of 50 cm3?
myrzilka [38]
Density = mass / volume

Mass = 5 kg

Volume = 50 cm³

d = 5 / 50

d = 0,1 kg/cm³

4 0
3 years ago
Use the given half reactions to "construct" an electrolytic cell. Zn^2+ + 2 e^--------->Zn E°cell = -0.76 V Cu^2+ + 2 e^-----
Neko [114]

Answer:

See explanation and image attached

Explanation:

The standard cell potential at 298 K is given by;

E°cathode - E°anode

Hence;

E°cell = 0.34 V - (-0.76 V)

E°cell = 0.34 V + 0.76 V

E°cell = 1.1 V

To reduce Zn^2+ to Zn then Zn must be the cathode, hence;

E°cell = (-0.76 V) - 0.34 V

E°cell = -1.1 V

5 0
3 years ago
Surface tension of solid,liquid and gas​
Arisa [49]

Explanation:

<h3>Surface tension is the tendency of liquid surfaces to shrink into the minimum surface area possible. Surface tension allows insects, usually denser than water, to float and slide on a water surface.</h3>

4 0
3 years ago
What is the increment of change in a series of straight-chain alkanes?
Tcecarenko [31]

What is the increment of change in a series of straight-chain alkanes?

CH

CH3

CH4

CH2

Answer:

CH2

6 0
1 year ago
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