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Anna [14]
4 years ago
7

Toluene (C7H8) and nitric acid (HNO3) are used in the production of trinitrotoluene (TNT, C7H5N3O6), an explosive. C7H8 + HNO3 =

> C7H5N3O6 + H2O (not balanced) (a) what mass in grams of nitric acid is required to react with 454 g C7H8 (b) what mass in grams of TNT can be made from 829 g C7H8 ?
Chemistry
1 answer:
olga55 [171]4 years ago
8 0
  The mass in grams  of nitric  acid that is required  to react  with 454g C7H8 is 932.72  grams

     calculation
find the  moles  of C7H8  used
moles = mass/molar mass

= 454 g/92  = 4.935  moles

balanced reacting  equation

C7H8  +3 HNO3  = C7H5N3O6  +3 H20
by  use of mole ratio between  C7H8  to  HNo3  which is  1:3  the moles of  HNO3  =4.935  x3 = 14.805  moles

mass of HNo3  =  moles  x molar mass
= 14.805  x 63  = 932.72  grams

part B

the  mass of  C7H5N3o6 = 2045.5 grams

calculate the moles of C7H8
= 829 g/92  g/mol  = 9.011  moles

by use of mole  ratio  between C7H8 to C7H5N3O6  which is  1:1  the moles of  C7H5N3O6  is also  = 9.011  moles

mass of  C7H5N3O6  is therefore  =  moles x molar mass

=9.011 x227  = 2045.5 grams
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Answer:

2.87 liter.

Explanation:

Given:

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Question asked:

What volume will the gas in the balloon occupy at 250 K ?

Solution:

By using:

Pv =nRT

Assuming pressure as constant,

V∝ T

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V = KT

Let initial volume of balloon , V_{1} = 4.3 liter

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4.3 liter = 4.3\times10^{-3}=4.3\times10^{-3} m^{3}

And initial temperature of balloon, T_{1} = 350 K

Let the final volume of balloon is V_{2}

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Now, V_{1} = KT_{1}

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V_{2} = KT_{2}

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Dividing equation 1 and 2,

\frac{4.3\times10^{-3}}{V_{2} } =\frac{K\times350}{K\times250}

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By cross multiplication:

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Now, convert it into liter with the help of calculation done above,

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