All categories

2 years ago

Which of the following is a step in constructing a circle circumscribed about a triangle

Mathematics

1 answer:

sweet-ann [11.9K]2 years ago

7 0

Answer:

Construct the perpendicular bisectors of each side

Choice A is correct

Step-by-step explanation:

Circumscribe means to draw on the outside of a geometric figure just touching the corner points but never crossing.

The steps in constructing a circle circumscribed about a triangle;

Construct the perpendicular bisector of one side

Construct the perpendicular bisector of another side

Where the lines cross is the center of the Circumscribed circle .

You might be interested in

Can someone help me?

Alexandra [31]

X=15, all you have to do is multiply

6 0

2 years ago

Read 2 more answers

What is the perimeter of triangle ABC. Coordinates A (4,-1) B (-1,4) C (0,-3)

meriva

Answer:

18.61

Step-by-step explanation:

6 0

2 years ago

Jesse bought a car for $25,000. The car depreciates approximately 10% of its value each year. What will the car be worth in 5 ye

givi [52]

Answer:

$12,500

Step-by-step explanation:

I got this answer by first taking the purchase price of the car and multiplying it by .10 to see what ten percent of the price was and I got $2,500. Then I took and multiplied 2,500 by 5 years and go 12,500. Then I subtracted 12,500 from the original purchase price to get $12,500. Meaning that the value of the care has decreased by half of the purchase price.

HOPE THIS HELPS!

4 0

2 years ago

Suppose a cold beer at 40°F is placed into a warm room at 70°F. Suppose 10 minutes later, the temperature of the beer is 48°F. U

Yuri [45]

Answer:

69.92°F

Step-by-step explanation:

Given:

Initial temperature ( i.e at time, t = 0) = 40°F

Temperature of the room = 70°F

Temperature after 10 minutes ( i.e at time t = 10 ) = 48°F

Now, from Newton's law of cooling

T'(t) = k(A - T(t))

T(t) temperature after time t

T'(t) = $\frac{\textup{dT}}{\textup{dt}}$

here, A is the room temperature

thus,

$\frac{\textup{dT}}{\textup{dt}}$ = k(70 - T)

$\frac{\textup{dT}}{\textup{70-T}}$ = kdt

on solving the differential equation, we get

T = $70-C^{-kt}$ ............(1)

Now from the boundary conditions,

i.e at time, t = 0; T = 40°F

we get,

40 = $70-C^{-k\times0}$

C = 30

and,

at time, t = 10; T = 48°F

thus,

48 = $70-30^{-k\times10}$

k = $\frac{\textup{-1}}{\textup{10}}ln\frac{11}{15}$

k = 0.03

Therefore,

for t = 25

from 1 we have

T = $70-30^{-0.03\times25}$

T = 70 - 0.0780

T = 69.92°F

3 0

2 years ago

Temperatures this cold are rare.

zhannawk [14.2K]

Answer:

-32°F

Step-by-step explanation:

8°F - 40°F

=> 32°F

3 0

2 years ago