Answer:
2,3 -Dimethyl pentane
Explanation:
The given molecule is 2,3-Dimethyl pentane.
First of all select the longest chain of C-C atom. This will be the parent name.
In given structure the longest chain is straight chain that contain five carbon. Thus the parent name will pentane and there is no double or triple bond the given structure is of alkane.
Than locate the positions of functional groups attached.
In given structure there are two methyl groups are present. Give the name in such a way that functional groups will have lowest number. In given case we will start from the left.
The first methyl group will have number 2 and second will have number 3.
The name will be,
2,3-Dimethyl pentane
I'll do A for you. They are all double displacement reactions. So recall: AB+CD--> CB+AD . Also, knowing the charges will help and make this so easy.
Answer:
C₂H₂ + 3H₂ ⟶ 2CH₄
Explanation:
The initial concentrations are:
[CH₄] = 6.30 ÷ 6.00 = 1.05 mol·L⁻¹
[C₂H₂] = 4.20 ÷ 6.00 = 0.700 mol·L⁻¹
[H₂] = 11.15 ÷ 6.00 = 1.858 mol·L⁻¹
2CH₄ ⇌ C₂H₂ + 3H₂
I/mol·L⁻¹: 1.05 0.700 1.858
![Q = \dfrac{\text{[C$_{2}$H$_{2}$][H$_{2}$]}^{3}}{\text{[CH$_{4}$]}^{2}} = \dfrac{ 0.700\times 1.858^{3}}{1.05^{2}}= 4.07](https://tex.z-dn.net/?f=Q%20%3D%20%5Cdfrac%7B%5Ctext%7B%5BC%24_%7B2%7D%24H%24_%7B2%7D%24%5D%5BH%24_%7B2%7D%24%5D%7D%5E%7B3%7D%7D%7B%5Ctext%7B%5BCH%24_%7B4%7D%24%5D%7D%5E%7B2%7D%7D%20%3D%20%5Cdfrac%7B%200.700%5Ctimes%201.858%5E%7B3%7D%7D%7B1.05%5E%7B2%7D%7D%3D%204.07)
Q > K
That means we have too many products.
The reaction will go to the left to get rid of the excess products.
C₂H₂ + 3H₂ ⟶ 2CH₄
Answer:
Do not use this exact photo please!
Explanation:
<span>all the ones that phase down are exothermic - freezing, deposition, condensation.
all the ones that phase up are endothermic - melting, sublimation, vaporization
endothermic is to gain heat, exothermic is to release heat</span>
