Answer: I would say its either exit door or the last one.
Explanation: Hope this helps plz mark brainliest.
Answer:
Total Kcal energy produced in the catabolism of mannoheptulose = 1184 Kcal
Explanation:
The molecular formula of mannoheptulose is C₇H₁₄O₇.
The structure is as shown in the attachment below.
Number of C-C bonds present in mannoheptulose = 6
Number of C-H bonds present in mannoheptulose = 8
Since the each C-C bond contains 76 Kcal of energy,
Amount of energy present in six C-C bonds = 6 * 76 = 456 Kcal
Also, since each C-H bond contains 91 Kcal of energy;
amount of energy present in eight C-H bonds = 8 * 91 = 728 Kcal
Total Kcal energy produced in the catabolism of mannoheptulose = 456 + 728 = 1184 Kcal
D. 1 proton and 1 neutron
The answer for the following question is explained below.
Therefore the total number of orbitals are " 9 ".
Explanation:
Orbital:
An orbital is a mathematical function that describes the wave-like behavior of an electron,electron pair,or the nucleons.
The total number of orbitals present in the 3rd energy level is 9.
Here,
A 3 s subshell has only one orbital.
A 3 p subshell has three orbitals.
A 3 d subshell has five orbitals.
Therefore the total number of orbitals is:
3 s = 1 orbital
3 p = 3 orbitals
3 d = 5 orbitals
total orbitals in 3rd energy level is = 1 + 3 + 5 =9
Therefore the total number of orbitals are " 9 ".