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UkoKoshka [18]
3 years ago
7

Suppose you are measuring the mass of a sample using a balance that employs a standard mass of density dw = 8.0 g/ml. what is th

e buoyancy correction (m/m\'), if the sample density is less than 8.0 g/ml?
Chemistry
1 answer:
sleet_krkn [62]3 years ago
5 0

The buoyant force formula is:

B = \rho Vg

where B is Buoyant force, \rho is density, V is displaced body volume and g is 9.806 ms^{-2} (standard gravity).

The standard mass density of the sample, \rho _{1} = 8 g/ml  

If the dansity of the sample, \rho _{2} < 8 g/ml

The buoyancy correction is determined by the ratio:

\frac{B_{1}}{B_{2}} = \frac{\rho_{1} Vg}{\rho_{2} Vg}

\frac{B_{1}}{B_{2}} = \frac{\rho_{1}}{\rho_{2}}

\frac{B_{1}}{B_{2}} = \frac{\rho_{1}}{\rho_{2}}>1

Hence, the the buoyancy correction is positive.

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An atom that normally has __________ electrons in its outer (valence) shell tends not to form chemical bonds with other atoms.
goblinko [34]
8 valence shell electrons.
5 0
3 years ago
In the equilibrium constant expression for the reaction below what is the correct exponent for N2O4?
irga5000 [103]
As we have the balanced reaction equation is:

N2O4 (g) ↔ 2NO2(g)

from this balanced equation, we can get the equilibrium constant expression

KC = [NO2]^2[N2O4]^1

from this expression, we can see that [NO2 ] is with 2 exponent of  the stoichiometric and we can see that from the balanced equation as NO2
is 2NO2 in the balanced equation.

and [N2O4] is with 1 exponent of the stoichiometric and we can see that from the balanced equation as N2O4 is 1 N2O4 in the balanced equation. 

∴ the correct exponent for N2O4 in the equilibrium constant expression is 1 
7 0
3 years ago
What neutral element has the electron configuration described by the Aufbau diagram above.​
devlian [24]

Answer:

Aluminium.

Explanation:

The above electronic configuration can be written in a simplified form as shown below:

1s² 2s²2p⁶ 3s²3p¹

Next, we shall determine the number of electrons in the atom of the element as follow:

Number electron = 2 + 2 + 6 + 2 + 1

Number of electron = 13

Next, we shall determine the number of protons.

Since the element is in its neutral state,

The number of electrons and protons are equal i.e

Proton = Electron

Number of electron = 13

Proton = Electron = 13

Proton = 13

Next, we shall determine the atomic number of the element.

The atomic number of an element is simply the number of protons in the atom of the element i.e

Atomic number = proton number

Proton = 13

Atomic number = 13

Comparing the atomic number of the element with those in the periodic table, the element with the above electronic configuration is aluminium since no two elements have the same atomic number.

5 0
3 years ago
The increasing concentration of a chemical as it moves through the links in a food chain is called ________.
algol13

Answer: Biological Magnification

Explanation:

Organisms acquire toxic substance from the environment along with nutrients and water. Some of the toxins are metabolized and excreted, but others accumulate in specific tissues, especially fat. One of the reasons accumulated toxins are particularly harmful is that the become more concentrated in successive trophic level of the food web, this is the process of biological magnification.

Magnification occurs because the biomass at any given level is produced from a must larger biomass ingested from the level below. Thus the top-level carnivores tend to be the organism most severely affected by toxic compounds in the environment.

Examples of toxins that demonstrate biology magnification are chlorinated hydrocarbons, and many pesticides.

4 0
3 years ago
The rate at which a certain drug is eliminated by the body follows first-order kinetics, with a half life of 68 minutes. Suppose
viva [34]

Answer:

The concentration would be; 0.0038 μgmL

Explanation:

Half life, t1/2 = 68 minutes

Initial Conc. [A]o = 0.12/μgmL

Final Conc [A] = ?

Time. k = 340 minutes

ln[A] = ln[A]o - kt

t1/2 = ln2 / k

k = 0.693 / t1/2  = 0.693 / 68 = 0.01019

ln[A] = ln (0.12) - 0.01019 (340)

ln[A] = -2.1203 -3.4646

ln[A] = -5.5849

[A] = 0.00375 ≈ 0.0038 μgmL

3 0
3 years ago
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