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UkoKoshka [18]
3 years ago
7

Suppose you are measuring the mass of a sample using a balance that employs a standard mass of density dw = 8.0 g/ml. what is th

e buoyancy correction (m/m\'), if the sample density is less than 8.0 g/ml?
Chemistry
1 answer:
sleet_krkn [62]3 years ago
5 0

The buoyant force formula is:

B = \rho Vg

where B is Buoyant force, \rho is density, V is displaced body volume and g is 9.806 ms^{-2} (standard gravity).

The standard mass density of the sample, \rho _{1} = 8 g/ml  

If the dansity of the sample, \rho _{2} < 8 g/ml

The buoyancy correction is determined by the ratio:

\frac{B_{1}}{B_{2}} = \frac{\rho_{1} Vg}{\rho_{2} Vg}

\frac{B_{1}}{B_{2}} = \frac{\rho_{1}}{\rho_{2}}

\frac{B_{1}}{B_{2}} = \frac{\rho_{1}}{\rho_{2}}>1

Hence, the the buoyancy correction is positive.

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Energy 1 mole of magnesium is being combusted, so to calculate the energy released when 1 mole of magnesium ( that is 24 g/mol of magnesium) is being combusted will be:

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