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GaryK [48]
3 years ago
15

Which of the following is the inverse function of y = 3x + 1?

Mathematics
2 answers:
Shalnov [3]3 years ago
4 0
Y= (x-1) /3 is the correct answer
Oksi-84 [34.3K]3 years ago
4 0

Answer:

Option C is the correct answer : y=\frac{(x-1)}{3}

Step-by-step explanation:

y=3x+1

For finding the inverse of this function, we will interchange x and y, then solve for y.

3y=x-1

y=\frac{x-1}{3}

Hence, option C is the correct answer : y=\frac{(x-1)}{3}

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Jane was paid $316 for 40 hours of work. Use compatible numbers to find about how much
Vinvika [58]

Answer:

$7.9 /hour

Step-by-step explanation:

$316/40 = $7. 9per hour

4 0
3 years ago
*15 points easy question*
maw [93]

Answer:

\sqrt{13}

Step-by-step explanation:

We are given an isosceles triangle. We need to remember the important rule that the base angles are equal. In this question we need to find the value of 'x' using a perpendicular height of 3 and a base length of 4. In this question we can half the triangle in half to help us find the value of x. Also we need to use Pythagoras theorem to help us find 'x'. Pythagoras states that a² + b² = c² so we want to find the hypotenuse of the triangle. If we half the triangle we get 2 triangle both with a base length of 2 and a perpendicular height of 3 so,

⇒ State Pythagoras theorem

→ a² + b² = c²

⇒ Substitute in the values

→ 3² + 2² = c²

⇒ Simplify

→ 9 + 4 = c²

⇒ Simplify further

→ 13 = c²

⇒ Square root both sides to find the value of 'c'

→\sqrt{13}  =  c

The value of x is the square root of 13

8 0
3 years ago
Which equation could have been used to create this graph
Temka [501]

Answer:

The answer is A

Hoped it helped <3 tell me if I am wrong

Step-by-step explanation:


4 0
3 years ago
Hello people ~
Luden [163]

Cone details:

  • height: h cm
  • radius: r cm

Sphere details:

  • radius: 10 cm

================

From the endpoints (EO, UO) of the circle to the center of the circle (O), the radius is will be always the same.

<u>Using Pythagoras Theorem</u>

(a)

TO² + TU² = OU²

(h-10)² + r² = 10²                                   [insert values]

r² = 10² - (h-10)²                                     [change sides]

r² = 100 - (h² -20h + 100)                       [expand]

r² = 100 - h² + 20h -100                        [simplify]

r² = 20h - h²                                          [shown]

r = √20h - h²                                       ["r" in terms of "h"]

(b)

volume of cone = 1/3 * π * r² * h

===========================

\longrightarrow \sf V = \dfrac{1}{3}  * \pi  * (\sqrt{20h - h^2})^2  \  ( h)

\longrightarrow \sf V = \dfrac{1}{3}  * \pi  * (20h - h^2)  (h)

\longrightarrow \sf V = \dfrac{1}{3}  * \pi  * (20 - h) (h) ( h)

\longrightarrow \sf V = \dfrac{1}{3} \pi h^2(20-h)

To find maximum/minimum, we have to find first derivative.

(c)

<u>First derivative</u>

\Longrightarrow \sf V' =\dfrac{d}{dx} ( \dfrac{1}{3} \pi h^2(20-h) )

<u>apply chain rule</u>

\sf \Longrightarrow V'=\dfrac{\pi \left(40h-3h^2\right)}{3}

<u>Equate the first derivative to zero, that is V'(x) = 0</u>

\Longrightarrow \sf \dfrac{\pi \left(40h-3h^2\right)}{3}=0

\Longrightarrow \sf 40h-3h^2=0

\Longrightarrow \sf h(40-3h)=0

\Longrightarrow \sf h=0, \ 40-3h=0

\Longrightarrow \sf  h=0,\:h=\dfrac{40}{3}<u />

<u>maximum volume:</u>                <u>when h = 40/3</u>

\sf \Longrightarrow max=  \dfrac{1}{3} \pi (\dfrac{40}{3} )^2(20-\dfrac{40}{3} )

\sf \Longrightarrow maximum= 1241.123 \ cm^3

<u>minimum volume:</u>                 <u>when h = 0</u>

\sf \Longrightarrow min=  \dfrac{1}{3} \pi (0)^2(20-0)

\sf \Longrightarrow minimum=0 \ cm^3

6 0
2 years ago
Read 2 more answers
Please Help! I have provided the screen shot
Alex_Xolod [135]
(3,-4)
is your answer
7 0
2 years ago
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