Answer:
14.9 g is the ideal yield of Cu(NO₃)₂
Explanation:
Reactants for the reaction: Cu and AgNO₃
Products: Copper nitrate and Ag
The balanced reaction is: Cu(s) + 2AgNO₃(aq) → 2Ag (s) + Cu(NO₃)₂
As the silver nitrate is in excess, the Cu will be the limiting reagent.
We convert the mass to moles → 5.05 g . 1 mol/ 63.55 g = 0.0794 moles
Ratio is 1:1, so 0.0794 moles will produce 0.0794 moles of Cupper(II) nitrate. We convert the moles to mass, and that value will be the theoretical yield.
0.0794 mol . 187.55 g /1 mol = of Cu(NO₃)₂
Its B
Explanation:
Thats should help you out
Answer:
0.3M
Explanation:
Step 1:
Data obtained from the question. This include the followingb:
Volume of acid (Va) = 90mL
Concentration of acid (Ca) = 0.2M
Volume of base (Vb) = 60mL
Concentration of base (Cb) =....?
Step 2:
The balanced equation for the reaction. This is given below:
HBr + NaOH —> NaBr + H2O
From the balanced equation above,
The mole ratio of the acid (nA) = 1
The mole ratio of the base (nB) = 1
Step 3:
Determination of the concentration of the base, NaOH.
The concentration of the base can be obtained as follow:
CaVa /CbVb = nA/nB
0.2 x 90 / Cb x 60 = 1
Cross multiply
Cb x 60 = 0.2 x 90
Divide both side by 60
Cb = 0.2 x 90 /60
Cb = 0.3M
Therefore, the concentration of the base, NaOH is 0.3M
Answer
C6H807 = 192.124 g/mol
n = m/M
n = 0.119 mol
Explanation:
to calculate amount in moles you need to find the molar mass of citric acid then divide the mass of the acid with the molar mass
