There is no table, but anything in the column under Flourine (F) has a -1 charge. Hope this helps :)
Answer:
15.1 seconds is the half life of the reaction when concentration of the substrate is 2.77 M.
Explanation:
A → B + C
The rate law of the reaction will be :
Initial rate of the reaction when concentration of the substrate was 0.4 M:
..[1]
Initial rate of the reaction when concentration of the substrate was 0.8 M:
...[2]
[1] ÷ [2] :
x = 0
The order of the reaction is zero.
For the value of rate constant ,k:
..[1]
x = 0
k= 0.183 M/s
The half life of the zero order kinetics is given by :
Where:
= Initial concentration of A
k = Rate constant of the reaction
So, the half-life for the decomposition of substrate 1 when the initial concentration of the substrate is 2.77 M:
15.1 seconds is the half life of the reaction when concentration of the substrate is 2.77 M.
Answer:
1st chemical equation → Chemical change
2nd chemical equation → Physical change
3rd chemical equation → Physical change
4th chemical equation → Chemical change
Explanation:
Chemical change has to the do with the creation of an entirely new product or substance. When two reactants react and form entirely new product(s), we say that a chemical change has occurred.
While a physical change does not create an entirely new substance or product; it can only change to a new form or state.
From the given equations, we discover that in the first equation, propane reacted with oxygen to give carbon (II) oxide and water (entirely new products) while in the second chemical equation, ethanol is a liquid (at room temperature) but later changes its state to gas (physical change).
The above answer is correct.