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2 years ago

How can you identify gas in a chemical reaction without observing the atoms or molecules?

Chemistry

1 answer:

nikitadnepr [17]2 years ago

5 0

Answer:

There are five signs of a chemical change:

Colour Change.

Production of an odour.

Change of Temperature.

Evolution of a gas (formation of bubbles)

Precipitate (formation of a solid).

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Construct a three-step synthesis of trans-2-pentene from acetylene by dragging the appropriate formulas into the bins. Note that

adelina 88 [10]

Answer:

The three-step synthesis of trans-2-pentene from acetylene is as follows.

Step -1: Formation of higher order terminal alkyne on reaction with sodium acetylides with haloalkanes.

Step -2: Formation terminal alkyne to nonterminal alkynes.

Step -3: Formation of trans-pent - 2-pent-ene by reduction.

Explanation:

Synthesis of trans-pent-2-yne from ethyne takes place is mainly a three step synthesis which involves formation of higher order terminal alkyne on reaction with sodium acetylides with haloalkane. Second step involves the further alkylation of terminal alkynes to higher order nonterminal alkynes and the third step involves the formation of trans-2-ene by dissolving reduction method.

The chemical reaction of each step of chemical reactions is as follows.

8 0

3 years ago

What are the oxidation numbers of K, Cl, and O in KClO,?

Tatiana [17]

Answer: Oxidation number of chlorine in potassium chlorate...

so, oxidation state of chlorine in potassium chlorate is +1. and yea!!

Explanation: hope this help

4 0

3 years ago

The substance water always has a mass ratio of 11% H to 89% O. If 5.00g of a substance containing H and O was decomposed into .2

Gre4nikov [31]

Answer:

No the substance is not water.

Explanation:

The balance chemical equation for the decomposition of water is as follow;

2 H₂O = 2 H₂ + O₂

Step 1: Calculate moles of H₂O;

Moles = Mass / M.Mass

Moles = 5.0 g / 18.01 g/mol

Moles = 0.277 moles of H₂O

Step 2: Calculate Moles of O₂ and H₂ produced by 0.277 moles of H₂O:

According to equation,

2 moles of H₂O produced = 1 mole of O₂

So,

0.277 moles of H₂O will produce = X moles of O₂

Solving for X,

X = 0.277 mol × 1 mol / 2 mol

X = 0.138 moles of O₂

Also,

According to equation,

2 moles of H₂O produced = 2 mole of H₂

So,

0.277 moles of H₂O will produce = X moles of H₂

Solving for X,

X = 0.277 mol × 2 mol / 2 mol

X = 0.227 moles of H₂

Step 3: Calculate Mass of O₂ and H₂ as;

For O₂:

Mass = Moles × M.Mass

Mass = 0.138 mol × 31.99 g/mol

Mass = 4.44 g of O₂

For H₂:

Mass = Moles × M.Mass

Mass = 0.227 mol × 2.01 g/mol

Mass = 0.559 g of H₂

Conclusion:

From conclusion it is proved that the amount of H₂ produced by decomposition of 5 g of water should be 0.559 g while in statement it is less i.e. 0.290 g.

6 0

3 years ago

What kind of chemical reaction does the chemical equation sodium + chlorine → sodium chloride represent?

scoundrel [369]

The answer is synthesis. This is a kind of reaction in which numerous reactants mix to make a single product. Synthesis responses discharge energy in the way of heat and light, so they are exothermic. An instance of a synthesis reaction is the creation of water from hydrogen and oxygen.

6 0

3 years ago

Read 2 more answers

Adding O2 to the reaction 6CO2 + 6H2O C6H12O6 + 6O2. WHICH WAY WILL THE REACTION SHIFT?

Oxana [17]

Answer:

The reaction will shift to the left to produce more reactants.

Explanation:

According to the Le- Chatelier principle,

At equilibrium state when stress is applied to the system, the system will behave in such a way to nullify the stress.

The equilibrium can be disturb,

By changing the concentration

By changing the volume

By changing the pressure

By changing the temperature

Consider the following chemical reaction.

Chemical reaction:

6CO₂ + 6H₂O ⇄ C₆H₁₂O₆ + 6O₂

In this reaction the equilibrium is disturb by increasing the concentration of Product.

When the concentration of product is increased the system will proceed in backward direction in order to regain the equilibrium. Because when product concentration is high it means reaction is not on equilibrium state. As the concentration of O₂ increased the reaction proceed in backward direction to regain the equilibrium state and more reactant is formed.

4 0

3 years ago