Answer:
ummmmmmmmmm what's that???
Answer:
0.9 mole of Fe(OH)3.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is given below:
Fe(NO3)3 + 3NaOH —> Fe(OH)3 + 3NaNO3
Now, we can determine the moles of iron (III) hydroxide formed from the reaction as follow:
From the balanced equation above,
3 moles of NaOH reacted to produce 1 mole of Fe(OH)3.
Therefore, 2.7 moles of NaOH will react to produce = 2.7/3 = 0.9 mole of Fe(OH)3.
Therefore, 0.9 mole of Fe(OH)3 is produced from the reaction.
<span> endothermic is the answer
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Answer:
1. Based on the given question, 138.03 grams of NO₂ is reacting completely with 18.02 grams of H2O. However, in case when 359 grams of NO₂ is used then the grams of water consumed in the reaction will be,
= 359 × 18.02 / 138.03 = 46.87 grams of water.
2. As mentioned in the given case 138.03 grams of NO₂ generates 126.04 grams of HNO₃. Therefore, 359 grams of NO₂ will produce,
= 359 × 126.04 / 138.03
= 327.81 grams of HNO₃.
3. Based on the given question, 138.04 grams of NO₂ is generating 30.01 grams of NO. Therefore, 359 grams of NO₂ will generate,
= 359 × 30.01 / 138.04
= 78.04 grams of NO.
