The givens are as follows: initial velocity (vi) = 6 m/sec acceleration = -9.8 m/sec^2 (the negative sign refers to the direction) final velocity (v) = 1.1 m/sec initial position (xi) = 0 meters
Now, we will use the equations of motion to get the displacement as follows: v = vi + at 1.1 = 6 - 9.8t 9.8t = 6-1.1 = 4.9 t = 0.5 sec
x = xi + vit + 0.5at^t x = 0 + (6)(0.5) + 0.5(-9.8)(0.5)^2 x = 1.775 meters