<h3>Given -:</h3>
change in emitter current, ∆l(E) = 4 mA
change in collector current,∆I(C) = 3.5 mA
<h3>To find -:</h3>
value of B
<h3>Solution :-</h3>
∆I(E) = ∆I(C) + ∆l(B), here ∆l(B) is the change in base current.
4 = 3.5 + ∆l(B)
∆I(B) = 0.5 mA
<h3>Now, B = ∆l (C) ÷ ∆l (B)</h3>
B = 3.5 ÷ 0.5
B = 7.0
<h3>so, the value of A = 7.0</h3>
21 is 42% of 50. To do that, you divide 21 by 50, you get .42. You then multiply .42 by 100 to get your answer.
3 years
15 = 250(0.06)
45/15 = 3
Answer:
44 +14i
Step-by-step explanation:
(5 + i)(9 + i)
FOIL
first 5*9 = 45
inner: 9i
outer :5i
last: i*i = i^2 = -1
Add togheter
45 + 9i+5i -1
Combine like terms
44 +14i
Answer:
69
Step-by-step explanation:
im big brain B)
