Answer: 52.17%
Explanation:
Number of matches in the box = 46
Number of matches that lit on the first strike = 22
Number of matches that did not light on the first strike = 46 - 22 = 24
Therefore, the percentage of the matches in the box did not light on the first strike will be:
= (Number of matches that did not light on the first strike / Number of matches in the box) × 100
= 24/46 × 100
= 52.17%
Therefore, the percentage of the matches in the box that did not light on the first strike is 52.17%.
Answer:
11482 ppt of Li
Explanation:
The lithium is extracted by precipitation with B(C₆H₄)₄. That means moles of Lithium = Moles B(C₆H₄)₄. Now, 1 mole of B(C₆H₄)₄ produce the liberation of 4 moles of EDTA. The reaction of EDTA with Mg²⁺ is 1:1. Thus, mass of lithium ion is:
<em>Moles Mg²⁺:</em>
0.02964L * (0.05581mol / L) = 0.00165 moles Mg²⁺ = moles EDTA
<em>Moles B(C₆H₄)₄ = Moles Lithium:</em>
0.00165 moles EDTA * (1mol B(C₆H₄)₄ / 4mol EDTA) = 4.1355x10⁻⁴ mol B(C₆H₄)₄ = Moles Lithium
That means mass of lithium is (Molar mass Li=6.941g/mol):
4.1355x10⁻⁴ moles Lithium * (6.941g/mol) = 0.00287g. In μg:
0.00287g * (1000000μg / g) = 2870μg of Li
As ppt is μg of solute / Liter of solution, ppt of the solution is:
2870μg of Li / 0.250L =
<h3>11482 ppt of Li</h3>
Explanation:
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The rate of change of
(g)=0.024M/s when the rate of change of
is – 0.012 M/s.
<h3>What is the rate of reaction?</h3>
Reaction rate, in chemistry, is the speed at which a chemical reaction proceeds.
→ ![CO_2(g)+2SO_2(g)](https://tex.z-dn.net/?f=CO_2%28g%29%2B2SO_2%28g%29)
![Rate = \frac{-dcs_2}{dt} =\frac{-do_2}{dt} =\frac{+dco_2}{dt} =\frac{1dso_2}{dt}](https://tex.z-dn.net/?f=Rate%20%3D%20%5Cfrac%7B-dcs_2%7D%7Bdt%7D%20%20%3D%5Cfrac%7B-do_2%7D%7Bdt%7D%20%3D%5Cfrac%7B%2Bdco_2%7D%7Bdt%7D%20%3D%5Cfrac%7B1dso_2%7D%7Bdt%7D)
Rate = \frac{-dcs_2}{dt} =\frac{-do_2}{dt} =\frac{+dco_2}{dt} =\frac{1dso_2}{dt}
Given:
![\frac{-dcs_2}{dt} =-0.012 M/s](https://tex.z-dn.net/?f=%5Cfrac%7B-dcs_2%7D%7Bdt%7D%20%3D-0.012%20M%2Fs)
![\frac{-dcs_2}{dt} =\frac{dso_2}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7B-dcs_2%7D%7Bdt%7D%20%3D%5Cfrac%7Bdso_2%7D%7Bdt%7D)
![\frac{dso_2}{dt}=0.024M/s](https://tex.z-dn.net/?f=%5Cfrac%7Bdso_2%7D%7Bdt%7D%3D0.024M%2Fs)
The rate of change of
(g)=0.024M/s
Hence, the rate of change of
(g)=0.024M/s
Learn more about the rate of change here:
brainly.com/question/13103052
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