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Makovka662 [10]
2 years ago
11

Drag each positive ion to bond it with a negative ion to form the neutral ionic compound indicated.

Chemistry
1 answer:
weeeeeb [17]2 years ago
8 0

Answer:

1. NaCl

2. NH4F

3. MgO

4.LiCl

5. KI

6. CaO

Explanation:

In that order

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The only nonmetal in Group 14 is<br> A carbon.<br> B. oxygen.<br> C. nitrogen.<br> D. fluorine.
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6 0
3 years ago
1. Methane (CH4) combusts as shown in the equation below. If 3 moles of methane were used in the combustion, what would be the c
umka2103 [35]

Answer:

The change in enthalpy in the combustion of 3 moles of methane = -2406 kJ

Explanation:

<u>Step 1: </u>The balanced equation

CH4(g) + 2 O2(g) → CO2(g) + 2 H2O(g)   ΔH = -802 kJ

<u>Step 2:</u> Given data

We notice that for 1 mole of methane (CH4), we need 2 moles of O2 to produce : 1 mole of CO2 and 2 moles of H20.

The enthalpy change of combustion, given here as  Δ H , tells us how much heat is either absorbed or released by the combustion of <u>one mole</u> of a substance.

In this case: we notice that the combustion of 1 mole of methane gives off (because of the negative number),  802.3 kJ  of heat.

<u>Step 3: </u>calculate the enthalpy change  for 3 moles

The -802 kj is the enthalpy change for 1 mole

The change in enthalpy for 3 moles = 3* -802 kJ = -2406 kJ

The change in enthalpy in the combustion of 3 moles of methane = -2406 kJ

5 0
3 years ago
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