Answer:
1.12 × 10⁻⁴ M
Explanation:
Step 1: Write the reaction for the solution of Mg(OH)₂
Mg(OH)₂(s) ⇄ Mg²⁺(aq) + 2 OH⁻(aq)
Step 2: Make an ICE chart
We can relate the solubility product constant (Ksp) with the solubility (S) through an ICE chart.
Mg(OH)₂(s) ⇄ Mg²⁺(aq) + 2 OH⁻(aq)
I 0 0
C +S +2S
E S 2S
The solubility product constant is:
Ksp = 5.61 × 10⁻¹² = [Mg²⁺] × [OH⁻]² = S × (2S)² = 4S³
S = 1.12 × 10⁻⁴ M
The reaction that should be followed is
Na2SO4 + C<span>a(NO3)2 --> CaSO4 + 2NaNO3</span>
first calculate the limiting reactant
mol Na2SO4 = 0.075 L (<span>1.54×10−2 mol / L) = 1.155x10-3 mol
mol Ca(NO3)2 = 0.075 L (</span><span>1.22×10−2 mol / L) = 9.15x10-4 mol
so the limiting reactant is the Ca(NO3)2
so all of the Ca2+ will be precipitated, percentage unprecipitated = 0.00 % </span>
Answer:
moles SO42- = 0.0500 L x 0.20 M=0.010
moles Ba2+ = 0.0500 L x 0.10 M = 0.0050
Ba2+ + SO42- = BaSO4 (s)
moles SO42- in excess = 0.010 - 0.0050=0.0050
total volume = 100 mL = 0.100 L
[SO42-]= 0.0050/0.100= 0.050 M
[Na2SO4] = 2 /2 = 1 M
moles Na2SO4 = 2 M x 0.500 L = 0.500
mass Na2SO4 = 0.500 x 142 g/mol=71.0 g
moles MgBr2 = 46 /184 =0.25
moles Br- = 0.25 x 2 = 0.50
[Br-]= 0.50 / 0.50 L = 1 M
Answer:
4.89 mol
Explanation:
Step 1: Write the balanced equation
This is a double displacement reaction.
3 CaSO₄ + 2 AIP ⇒ Ca₃P₂ + AI₂(SO₄)₃
Step 2: Establish the appropriate molar ratio
According to the balanced equation, the molar ratio of CaSO₄ to AlP is 3:2.
Step 3: Calculate the moles of AlP needed to react with 7.33 moles of CaSO₄
We will use the previously established molar ratio.
7.33 mol CaSO₄ × 2 mol AlP/3 mol CaSO₄ = 4.89 mol AlP
Answer: b) loses.
Explanation: As the pendulum swings back and forth, the balance between the two types of energy changes constantly. At some points in its swing, the pendulum has more kinetic energy. At other points, it has more potential energy. No pendulum can swing forever because the system loses energy on account of friction.
