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nalin [4]
3 years ago
8

How many pi bonds are present in a molecule of HCP?

Chemistry
1 answer:
Anestetic [448]3 years ago
6 0

Answer:

2

Explanation:

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How much energy would be released if 1.0 g of material were completely converted into energy?
natali 33 [55]
Using this formula E = mc2, which is the formula formulated by Albert Einstein to get the energy where E is the units of energy, m is the mass and c is the speed of light. We can say that 1 g is equivalent to 0.001 kg. The speed of light is 38<span>. Substituting these values to the formula, we can get 90 terajoules.</span>
3 0
4 years ago
Entalpy of vaporization of water is 41.1k/mol. if the vapor pressure of water at 373k is 101.3 kpa, what is the vapor pressure o
allsm [11]

Answer: The vapor pressure of water at 298 K is 3.565kPa.

Explanation:

The vapor pressure is determined by Clausius Clapeyron equation:

ln(\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}(\frac{1}{T_1}-\frac{1}{T_2})

where,

P_1 = initial pressure at 298 K = ?

P_2 = final pressure at 373 K = 101.3 kPa

\Delta H_{vap} = enthalpy of vaporisation = 41.1 kJ/mol = 41100 J/mol

R = gas constant = 8.314 J/mole.K

T_1 = initial temperature = 298 K

T_2 = final temperature = 373 K

Now put all the given values in this formula, we get

\log (\frac{101.3}{P_1})=\frac{41100}{2.303\times 8.314J/mole.K}[\frac{1}{298K}-\frac{1}{373K}]

\frac{101.3}{P_1}=antilog(1.448)

P_1=3.565kPa

Therefore, the vapor pressure of water at 298 K is 3.565kPa.

3 0
4 years ago
Which of the following description of the moons surface is accurate?
maria [59]
The answer is B) dry and irregular
4 0
4 years ago
Read 2 more answers
What steps would you take in a lab to prepare 1000 mL of a 2 M NaCl solution
amm1812

Answer:

The answer to your question is below

Explanation:

Data

Volume = 1000 ml

Concentration = 2M

molecule = NaCl

Process

1.- Calculate the number of moles of NaCl

Molarity = moles/Volume

-Solve for volume

moles = Molarity x Volume (liters)

-Substitution

moles = 2 x 1

-Result

moles = 2

2.- Determine the molar mass of NaCl

NaCl = 23 + 35.5 = 58.5 g

3.- Calculate the mass of NaCl to prepare the solution

               58.5 g -----------------  1mol

                   x      -----------------  2 moles

                       x = (2 x 58.5) / 1

                       x = 117g

4.- Weight 117 g of NaCl, place them in a volumetric flask (1 l), and add enough water to prepare the solution.

7 0
4 years ago
Zinc phosphide, Zn3P2, is often used as a rat poison. Phosphorus has 5 valence electrons. Assuming that phosphorus is following
Nadya [2.5K]

Answer:

Two electrons each!

Explanation:

The question pretty much requires us to find the oxidation number of Zinc in the compound.

Zn3P2

Following oxidation number rules;

O.N of Zn3P2 = 0

.Since phosphorus has valence of 5, it needs three more electrons to achieve its octet state. Hence;

Oxidation number of P = -3

Let oxidation number of Zn = x

We have;

3x  +  2 (-3) = 0

3x + (-6) = 0

3x = 6

x = 6/3 = 2

This means each zn electrons lost 2 electrons.

4 0
3 years ago
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