Question

Jason and Jeremy work together at a juggling-ball factory. Jason lives 25 miles away from the factory and drives at 60 miles per hour. Jeremy lives 35 miles away from the factory and drives at 70 miles per hour.
If they leave their houses at the same time, then

(a) who arrives at the factory first ?, and

(b) how long is it until the other person arrives?

Answer 1

(a) Jason arrives at the factory first

(b) It takes 5 minutes until the other person arrives

Step-by-step explanation:

Jason and Jeremy work together at a juggling-ball factory

• Jason lives 25 miles away from the factory and drives at 60 miles per hour
• Jeremy lives 35 miles away from the factory and drives at 70 miles per hour
• They leave their houses at the same time

We need to know who arrives at the factory first and how long it is until the other person arrives

Time = Distance ÷ speed

∵ Jason lives 25 miles away from the factory

∴ The distance = 25 miles

∵ He drives at 60 miles per hour

∴ The speed = 60 miles per hour

- Use the rule above to find the time

∵ Time = 25 ÷ 60 = $\frac{5}{12}$ hour

∵ 1 hour = 60 minutes

∴  $\frac{5}{12}$ hour =  

∴ Jason arrives to the factory in 25 minutes

∵ Jeremy lives 35 miles away from the factory

∴ The distance = 35 miles

∵ He drives at 70 miles per hour

∴ The speed = 60 miles per hour

- Use the rule above to find the time

∵ Time = 35 ÷ 70 = $\frac{1}{2}$ hour

∵  $\frac{1}{2}$ hour =  

∴ Jeremy arrives to the factory in 30 minutes

∵ They leave their houses at the same time

∵ 25 minutes < 30 minutes

∴ Jason arrives first

(a) Jason arrives at the factory first

∵ Jason arrives to the factory in 25 minutes

∵ Jeremy arrives to the factory in 30 minutes

∵ 30 - 25 = 5 minutes

∴ Jeremy arrives after Jason by 5 minutes

(b) It takes 5 minutes until the other person arrives

Learn more:

You can learn more about the rules of motion in brainly.com/question/2088710

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