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german
3 years ago
14

Evaluate the expression. [3(15 + 4)^2 + 2(20 + 5)^2]^0 A) 0 B) 1 C) 2 D) 5

Mathematics
1 answer:
ziro4ka [17]3 years ago
5 0

Answer:

1 thus b: is the Answer

Step-by-step explanation:

Simplify the following:

(3 (15 + 4)^2 + 2 (20 + 5)^2)^0

(3 (15 + 4)^2 + 2 (20 + 5)^2)^0 = 1:

Answer:  1

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Find the common difference for the arithmetic sequence. 1.7, 2.7, 3.7 4.7.....
Anni [7]

Answer:

Step-by-step explanation:

You do not need to where the formula comes from but, just for fun, here’s a hint

To add up the numbers 1 to 10

Write out the numbers

1 2 3 4 5 6 7 8 9 10

Write them backwards

10 9 8 7 6 5 4 3 2 1

Add up both lists

11  11  11  11  11  11  11  11  11 11

This is 10 × 11 = 110

But this is twice the sum as two lots were added together

So the sum of the numbers 1 to 10 is 110 ÷ 2 = 55

 

ArSeqSum Notes fig4, downloadable IGCSE & GCSE Maths revision notes

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3 years ago
Zeba wants to place her four dolls on the four shelves,one doll on each shelf .in how many ways can she arrange all toys
nikdorinn [45]

Answer:

Step-by-step explanation:

24   hope it helps you!!

4 0
3 years ago
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Can somebody please tell me what 1/2x3/4 is.
Ad libitum [116K]

Answer: 3/8

Step-by-step explanation:

1/2 × 3/4

Multiply the numerators: 1 × 3 = 3

Multiply the denominators: 2 × 4 = 8

I hope this is clear, have a great day.

8 0
3 years ago
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Please answer correctly !!!! Will mark brainliest !!!!!!!!!!!!
andrezito [222]

Answer:

7-x

Step-by-step explanation:

49 - x^2 is a perfect square so

it factors to :(7+x)(7-x)

since there is a negative in 49 - x^2, it would make sense that the answer would be a negative to get that negative answer in the first place (negative times a positive equals a negative)

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8 0
3 years ago
Can you please help? The question is in the picture picture. thank you
Naddika [18.5K]

Given:

The value is \dfrac{\sqrt{2}}{2}.

To find:

The values from the given options which are equal to the given value.

Solution:

We have,

\dfrac{\sqrt{2}}{2}

It can be written as:

\dfrac{\sqrt{2}}{2}=\dfrac{1}{\sqrt{2}}

From the standard trigonometric table, we get

\sin 30^\circ=\dfrac{1}{2}

\sin 45^\circ=\dfrac{1}{\sqrt{2}}

\cos 45^\circ=\dfrac{1}{\sqrt{2}}

\cos 60^\circ=\dfrac{1}{2}

\tan 30^\circ=\dfrac{1}{\sqrt{3}}

\tan 45^\circ=1

From the above values it is clear that the value of \sin 45^\circ and \cos 45^\circ are equal to \dfrac{1}{\sqrt{2}}.

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3 years ago
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