Answer: 367 grams
Explanation:
According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number of particles.
Enthalpy of vaporization is the amount of heat released when 1 mole of substance is converted from liquid to gaseous state.
Given : Enthalpy of vapourization of = 17.4 kJ/mol
To calculate the number of moles, we use the equation:
1 mole of produces heat = 17.4 kJ
8.3 moles of produces heat =
Given : Enthalpy of vapourization of = 6.0 kcal/mol =
(1kcal=4.184kJ)
25.104 kJ heat is produced by = 1 mole of
144 kJ heat is produced by = of
Mass of
Thus 367 grams of must be evoparated o remove as much heat as evaporation of 1.00 kg of