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saveliy_v [14]
3 years ago
7

4. A,B,AB or O. 5. A,B,AB or O 6. A,B,AB or O

Chemistry
1 answer:
Gemiola [76]3 years ago
5 0

Answer:

4. Blood types B and O

5. Blood types B and O

6. Blood types A, B AB, and O

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A chemical reaction takes place inside a flask submerged in a water bath. The water bath contains 8.10kg of water at 33.9 degree
lions [1.4K]

Answer:

The new temperature of the water bath 32.0°C.

Explanation:

Mass of water in water bath ,m= 8.10 kg = 8100 g ( 1kg = 1000g)

Initial temperature of the water = T_1=33.9^oC=33.9+273K=306.9 K

Final temperature of the water = T_2

Specific heat capacity of water under these conditions =  c = 4.18 J/gK

Amount of energy lost by water = -Q = -69.0 kJ = -69.0 × 1000 J

( 1kJ=1000 J)

Q=m\times c\times \Delta T=m\times c\times (T_2-T_1)

-69.0\times 1000 J=8100 g\times 4.18 J/g K\times (T_2-306.9 K)

-69,000.0 J=8100 g\times 4.18 J/g K\times (T_2-306.9 K)

T_2=304.86 K=304.86 -273^oC=31.86^oC\approx 32.0^oC

The new temperature of the water bath 32.0°C.

5 0
4 years ago
which of the following is a balanced chemical equation for the reaction of magnesium with nitrogen gas to form magnesium nitride
ioda
So the unbalanced equation would be Mg + N^2 --> Mg^3N^2

Which means the balanced equation would be 3Mg + N^2 --> Mg^3N^2

This is balance the equation out since you now has 3 magnesium and 2 nitrogen on the left side, and 3 magnesium on 2 nitrogen on the right. Double check my work though, it's been awhile.
8 0
4 years ago
Determine the mass in 3.57 mol Al.
Alborosie

Answer:

b

Explanation:

8 0
2 years ago
Read 2 more answers
PLEASE HELP ME<br><br> what would be the mass of 9.03 x 1021 molecules of hydrobromic acid (HBr)?
Nikitich [7]

We know 1 mole of any atom or molecules contains 6.033 \times 10^{23} atom or molecules.

1 mole of HBr i.e 81 gm/mol contains  6.033 \times 10^{23} atom or molecules.

So, mass of 9.03\times 10^{21} molecules is :

m=\dfrac{81\times 9.03\times 10^{21} }{6.033 \times 10^{23}}\\\\m= 1.21\ gm

Therefore, mass of  9.03\times 10^{21} molecules is 1.21 gm .

Hence, this is the required solution.

7 0
3 years ago
How many molecules are in 4.08 moles of CCL4
Likurg_2 [28]
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3 years ago
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