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Sergio039 [100]
3 years ago
12

Balanced equation for solid magnesium oxide

Chemistry
1 answer:
Y_Kistochka [10]3 years ago
3 0

Answer:

Mg + O2 → MgO

Explanation:

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Calculate [OH − ], pOH, and pH for each of the following. (Assume that all solutions are at 25°C.) (a) 0.00013 M Ca(OH)2 [OH − ]
MA_775_DIABLO [31]

Answer:

See image attached

Explanation:

The hydroxide ion concentration can easily be calculated from the concentration of the metal hydroxide solutions given as shown in the solution attached. The pH can now be obtained from there using pH+pOH=14. The pH value is always greater than the the pOH value as shown in the solution to the problems attached.

Question (c) contains incorrect data that cannot be used to calculate the required parameters.

5 0
3 years ago
In one or two sentences, explain why the combined weight of several liquids mixed in an open flask can be less than but never mo
exis [7]

Answer:

j

Explanation:

h

6 0
2 years ago
8. Which of the following statements about noble gases is correct?
Tanya [424]

Answer:

C.

Explanation:

Noble gases are stable and already have a full outter shell therefore don't tend to lose or gain any electrons.

8 0
3 years ago
Heat that flows by conduction is the transfer of thermal energy between substances in contact. What must occur for this to happe
iragen [17]
Is this the full question?

<span>Heat that flows by conduction is the transfer of thermal energy between substances in contact. For this to happen, what must occur?

A) The two systems must be the same temperature.
B) The two systems must not be touching each another.
C) One system must have higher kinetic energy than the other system.
D) The thermal energy of one system must be the same as the thermal energy of the other system.</span>
6 0
3 years ago
Read 2 more answers
In an experiment designed to determine the concentration of Cu 2 ions in an unknown solution, you need to prepare 100 mL of 0.10
Alexxandr [17]

Answer:

1.6 grams

Explanation:

We need to prepare 100 mL (0.100 L) of a 0.10 M CuSO₄ solution. The required moles of CuSO₄ are:

0.100 L × 0.10 mol/L = 0.010 mol

The molar mass of CuSO₄ is 159.61 g/mol. The mass corresponding to 0.010 moles is:

0.010 mol × (159.61 g/mol) = 1.6 g

We should use 1.6 grams of CuSO₄.

8 0
3 years ago
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