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alex41 [277]
3 years ago
5

How many sig figs are in the measurment 10010m

Chemistry
1 answer:
PSYCHO15rus [73]3 years ago
3 0

Answer:

5

Explanation:

They all matter unless it is a decimal.

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What are the natural components of water?
DerKrebs [107]

two hydrogen atoms and one oxygen atom. hope this helped.

7 0
3 years ago
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According to the video on nuclear power plants, what does PWR stand for?
Radda [10]

PWR stands for many things. Since you're talking about nuclear power reactors I think PWR stands for pressurized water reactor.

A pressurized water reactor follows many steps but the main goal is to obtain thermal energy from water.



Hope it helped,



BioTeacher101

6 0
3 years ago
Please HELP! Use the following Equations to answer the problem: CH3OH + O2 —> CO2 + H2O
snow_lady [41]

Answer:

The answer to your question is below

Explanation:

1)

Balanced chemical reaction

              2CH₃OH  + 3O₂  ⇒    2 CO₂  +  4H₂O

          Reactant            Element         Product

                2                         C                    2

                8                         H                    8

                8                         O                    8        

Molar mass of CH₃OH = 2[12 + 16 + 4]

                                     = 2[32]

                                     = 64 g

Molar mass of O₂ = 3[16 x 2] = 96 g

Theoretical proportion CH₃OH/O₂ = 64 g/96g = 0.67

Experimental proportion CH₃OH/O₂ = 60/48 = 1.25

Conclusion

The limiting reactant is O₂ because the Experimental proportion was higher than the theoretical proportion

2)

Balanced chemical reaction

                         S₈  +  12O₂  ⇒    8SO₃

             Reactant     Elements     Products

                    8                  S                8

                   24                 O              24

Molar mass of S₈ = 32 x 8 = 256 g

Molar mass of O₂ = 12 x 32 = 384 g

Theoretical proportion S₈ / O₂ = 256 / 384

                                                  = 0.67

Experimental proportion S₈ / O₂ = 40 / 35

                                                     = 1.14

Conclusion

The limiting reactant is O₂ because the experimental proportion was lower than the theoretical proportion.          

6 0
4 years ago
Suppose that a student doing this experiment ran into some procedural and calculation difficulties. State the effect each of the
Bingel [31]
The only one i can make sense out of would be: <span>
(1) "</span><span>After the reaction was completed, the student failed to withdraw the rod to its original position before taking the second buret reading." </span><em>this would affect the volume, since the rod is submerged in the solution, it would affect the reading (it would appear as a greater volume).</em>
5 0
3 years ago
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How much heat is required to warm 50.0 g of ice from -10.0oC to 0.00oC, melt the ice, warm the water from 0.00oC to 100.0oC, boi
ludmilkaskok [199]

The total heat required to convert the ice to steam is 155,000 J.

The given parameters:

  • <em>Mass of the ice, m = 50 g</em>
  • <em>Initial temperature of the ice, t = -10 ⁰C</em>
  • <em>Final temperature of the ice, T = 0⁰C, 100⁰C and 120⁰C</em>
  • <em>Specific heat capacity of water = 4.184 J/g⁰C</em>
  • <em>Heat of fusion of ice, = 333.55 J/g</em>
  • <em>Heat of vaporization, = 2,230 J/g</em>

<em />

The heat required to raise the temperature to 0⁰C is calculated as;

Q  = mc\Delta t\\\\Q_1 = 50 \times 4.184 \times (0 - (-10))\\\\Q_1 = 2092 \ J

The  heat required to melt the ice is calculated as follows;

Q_2 = mL_f\\\\Q_2 = 50 \times 333.55 \\\\Q_2 = 16,677.5 \ J

The heat raise the temperature to 100⁰C is calculated as;

Q_3 = 50 \times 4.184 \times (100 - 0)\\\\Q_3 = 20,920 \ J

The  heat required to boil the water is calculated as follows;

Q_4 = mL_v\\\\Q_4 = 50 \times 2230\\\\4_4 = 111,500 \ J

The heat raise the temperature to 120⁰C is calculated as;

Q_5 = 50 \times 4.184 \times (120 - 100)\\\\Q_5 = 4,184 \ J

The total heat required is calculated as follows;

Q_t = Q_1 + Q_2 + Q_3 + Q_4 + Q _5 \\\\Q_t  = 2092 + 16,677.5 + 20,920 + 111,500 + 4,184\\\\Q_t = 155,373.5 \ J\\\\Q_t \approx 155,000 \ J

Learn more about heat capacity here: brainly.com/question/16559442

4 0
3 years ago
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