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4 years ago

Solve for u. -3= -1/u+1

Mathematics

2 answers:

Inga [223]4 years ago

8 0

Answer:

u = -2/3

Step-by-step explanation:

-3 = -1/ (u+1)

Multiply each side by (u+1)

-3 *(u+1) = -1/ (u+1) * (u+1)

-3 (u+1) = -1

Distribute

-3u -3 = -1

Add 3 to each side

-3u -3+3 = -1+3

-3u = 2

Divide each side by -3

-3u/-3 = 2/-3

u = -2/3

jolli1 [7]4 years ago

3 0

Answer:

-2/3

Step-by-step explanation:

multiply each side by u +1 to get it out of the denominator

-3(u + 1) = -1

now use distributive property

-3u - 3 = -1

add the 3 to move it over

-3u = 2

now divide by -3

u = -2/3

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Step-by-step explanation:

About the easiest way to do this for small values of n is to compute each of the terms using the given recurrence relation.

$a_1=4\\\\a_2=-3a_1=-3(4)=-12\\\\a_3=-3a_2=-3(-12)=36\\\\a_4=-3a_3=-3(36)=-108\\\\\boxed{a_4=-108}$

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<em>Alternate solution</em>

You recognize that the recurrence relation describes a geometric sequence with a first term of 4 and a common ratio of -3. The n-th term of a geometric sequence is ...

$a_n=a_1\cdot r^{n-1} \qquad\text{for first term $a_1$ and common ratio $r$}$

Then the 4th term will be ...

$a_4=4\cdot(-3)^{4-1}=4\cdot(-27)=-108$

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