In this case, according to the given information about the oxidation numbers anf the compounds given, it turns out possible to figure out the oxidation number of manganese in both MnI2, manganese (II) iodide and MnO2, manganese (IV) oxide, by using the concept of charge balance.
Thus, we can define the oxidation state of iodine and oxygen as -1 and -2, respectively, since the former needs one electron to complete the octet and the latter, two of them.
Next, we can write the following 
, since manganese has five oxidation states, and it is necessary to calculate the appropriate ones:
Next, we multiply each anion's oxidation number by the subscript, to obtain the following:
Thus, the correct choice is Manganese has an oxidation number of +2 in Mnl2 and +4 in MnO2.
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No idea.. I think if you take angle (<) MNL then divide those...
Answer:
Fossil Fuels have the ability to pollute and trash our ecosystems. Its better for us to use clean and renewable energy too.
Explanation:
<u>Answer:</u>
<u>For a:</u> The volume of the box is 217.5 mL
<u>For b:</u> The volume of the box is 0.2175 L
<u>Explanation:</u>
The box is a type of cuboid.
To calculate the volume of cuboid, we use the equation:
where,
V = volume of cuboid
l = length of cuboid = 10.00 cm
b = breadth of cuboid = 7.25 cm
h = height of cuboid = 3.00 cm
Putting values in above equation, we get:
To convert the volume of cuboid into milliliters, we use the conversion factor:
So,
Hence, the volume of the box is 217.5 mL
To convert the volume of cuboid into liters, we use the conversion factor:
So,
Hence, the volume of the box is 0.2175 L
<h3>Answer:</h3>
The New pressure (750 mmHg) is greater than the original pressure (500 mmHg) hence, the new volume (6.0 mL) is smaller than the original volume (9.0 mL).
<h3>Solution:</h3>
According to Boyle's Law, " <em>The Volume of a given mass of gas at constant temperature is inversely proportional to the applied Pressure</em>". Mathematically, the initial and final states of gas are given as,
P₁ V₁ = P₂ V₂ ----------- (1)
Data Given;
P₁ = 500 mmHg
V₁ = 9.0 mL
P₂ = 750 mmHg
V₂ = ??
Solving equation 1 for V₂,
V₂ = P₁ V₁ / P₂
Putting values,
V₂ = (500 mmHg × 9.0 mL) ÷ 750 mmHg
V₂ = 6.0 mL
<h3>Result:</h3>
The New pressure (750 mmHg) is greater than the original pressure (500 mmHg) hence, the new volume (6.0 mL) is smaller than the original volume (9.0 mL).
