<span>More surface area --> more molecules of the solute in contact with the solvent --> more chance for a solvent molecule to collide with the solute molecules --> dissolves faster
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Answer:
The number ratio is 4:7
Explanation:
Step 1: Data given
Compound 1 has 50.48 % oxygen
Compound 2 has 36.81 % oxygen
Molar mass oxygen = 16 g/mol
Molar mass manganese = 54.94 g/mol
Step 2: Calculate % manganes
Compound 1: 100 - 50.48 = 49.52 %
Compound 2: 100 - 36.81 = 63.19 %
Step 3: Calculate mass
Suppose mass of compounds = 100 grams
Compound 1:
50.48 % O = 50.48 grams
49.52 % Mn = 49.52 grams
Compound 2:
36.81 % O = 36.81 grams
63.19 % Mn = 63.19 grams
Step 4: Calculate moles
Compound 1
Moles O = 50.48 grams / 16.0 g/mol = 3.155 moles
Moles Mn = 49.52 grams / 54.94 g/mol = 0.9013 moles
Compound 2
Moles O = 36.81 grams / 16.0 g/mol = 2.301 moles
Moles Mn = 63.19 grams / 54.94 g/mol = 1.150 moles
Step 5: calculate mol ratio
We will divide by the smallest amount of moles
Compound 1
O: 3.155/0.9013 = 3.5
Mn: 0.9013 / 0.9013 = 1
Mn2O7
Compound 2
O: 2.301 / 1.150 = 2
Mn: 1.150 / 1.150 = 1
MnO2
The number ratio is 2:3.5 or 4:7
Answer:
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Explanation:
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19NBoli
During photosynthesis, 5 moles of water are needed to produce 150 grams of glucose. The correct option is D.
<h3>What is photosynthesis?</h3>
It is the process by which green plants and some other organisms use sunlight to synthesize nutrients from carbon dioxide and water.
- Step 1: Write the balanced equation for photosynthesis.
6 CO₂ + 6 H₂O ⇒ C₆H₁₂O₆ + 6 O₂
- Step 2: Convert 150 g of C₆H₁₂O₆ to moles.
The molar mass of C₆H₁₂O₆ is 180.16 g/mol.
150 g × 1 mol/180.16 g = 0.833 mol
- Step 3: Calculate the moles of water required to form 0.833 moles of C₆H₁₂O₆
The molar ratio of H₂O to C₆H₁₂O₆ is 6:1.
0.833 mol C₆H₁₂O₆ × 6 mol H₂O/1 mol C₆H₁₂O₆ = 5.00 mol H₂O
During photosynthesis, 5 moles of water are needed to produce 150 grams of glucose. The correct option is D.
Learn more about photosynthesis here: brainly.com/question/3529377
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