1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
meriva
3 years ago
13

Which of the following is true of science? (2 points)

Chemistry
1 answer:
Tju [1.3M]3 years ago
7 0

Answer:

It is based on testable and replicable evidence.

You might be interested in
Copper(I) ions in aqueous solution react with NH 3 ( aq ) according to Cu + ( aq ) + 2 NH 3 ( aq ) ⟶ Cu ( NH 3 ) + 2 ( aq ) K f
Kruka [31]

Answer:

53.18 gL⁻¹

Explanation:

Given that:

Cu^{2+}_{(aq)} + 2NH_{3(aq)} ------>  [Cu(NH_3)_2]^+_{(aq)}      ------equation (1)

where;

Formation Constant  (k_f) = 6.3*10^{10}

However, the Dissociation of CuBr_{(s) yields:

CuBr_{(s)}      ⇄    Cu^{+}_{(aq)}  + Br^-_{(aq)}      -------------- equation (2)

where;

the Solubility Constant (k_{sp})  = 6.3 *10^{-9

From equation (1);

(k_f) = \frac{[[Cu(NH_3)_2]^+]}{[Cu^{2+}][NH_3]^{2}}            ---------  equation (3)

From equation (2)

(k_{sp})  = [Cu^+][Br^-]           ---------  equation (4)

In NH_3, the net reaction for CuBr_{(s) can be illustrated as:

CuBr_{(s)   + 2NH_{3(aq)}  ⇄  [Cu(NH_3)_2]^+_{(aq)}  + Br^-_{(aq)}

The equilibrium constant (K) can be written as :

K=\frac{[[Cu(NH_3)_2]^+][Br^-]}{[NH_3]^2}

If we multiply both the numerator and the denominator with  [Cu^+] ; we have:

K=\frac{[[Cu(NH_3)_2]^+][Br^-]}{[NH_3]^2}*\frac{[Cu^+]}{[Cu^+]}

K=\frac{[[Cu(NH_3)_2]^+}{[NH_3]^2[Cu^+]}*{[Cu^+][Br^-]}

K = k_f *k_{sp}

K= (6.3*10^{10})*(6.3*10^{-9})

K= 3.97*10^2

K ≅ 4.0*10^2

Now; we can re-write our equilibrium constant again as:

K=\frac{[[Cu(NH_3)_2]^+][Br^-]}{[NH_3]^2}

4.0*10^2 = \frac{(x)(x)}{(0.76-2x)^2}

4.0*10^2 = \frac{(x)^2}{(0.76-2x)^2}

4.0*10^2 = (\frac{(x)}{(0.76-2x)})^2

By finding the square of both sides, we have

\sqrt {4.0*10^2} = \sqrt {(\frac{(x)}{(0.76-2x)})^2

2.0*10 = \frac{x}{(0.76-2x)}

20(0.76-2x) =x

15.2 -40x=x

15.2 = 40x +x

15.2 = 41x

x = \frac{15.2}{41}

x = 0.3707 M

In gL⁻¹; the solubility of CuBr_{(s) in 0.76 M NH_3 solution will be:

= \frac{0.3707 mole of CuBr}{1L}*\frac{143.45 g}{mole of CuBr}

=  53.18 gL⁻¹

4 0
3 years ago
If you have 1kg of carbon and 1 kg of gold, they will weigh the same.
Mekhanik [1.2K]
This would be be true
8 0
3 years ago
15.0 g of Fe and 25.0 g of sand are added to 250.0 g of water. a. Determine the percent mass of Fe, sand, and water in the mixtu
lana [24]

Answer:

A. percentage mass of iron = 5.17%

percentage mass of sand  = 8.62%

percentage mass of water = 86.205%

B. (Iron + sand + water) -------> ( iron + sand) ------> sand

C. The step of separation of iron and sand

Explanation:

A. Percentage mass of the mixtures:

Total mass of mixture = (15.0 + 25.0 + 250.0) g =290.0 g

percentage mass of iron = 15/290 * 100% = 5.17%

percentage mass of sand = 25/290 * 100% = 8.62%

percentage mass of water = 250/290 * 100% = 86.205%

B. Flow chart of separation procedure

(Iron + sand + water) -------> separation by filtration using filter paper and funnel to remove water --------> ( iron + sand) -----------> separation using magnet to remove iron ------> sand

C. The step of separation of iron and sand by magnetization of iron will have the highest amount of error because during the process, some iron particles may not readily be attracted to the magnet as they may have become interlaced in-between sand grains. Also, some sand particle may also be attracted to the magnet as they are are borne on iron particles.

5 0
3 years ago
Which of the following is the largest? cg, dg, mg, or ng
katrin [286]
The correct answer is:  [C]:  " mg " {"milligrams"} .
_____________________________________________________
4 0
3 years ago
Read 2 more answers
A voltaic cell is created by using a copper cathode and a magnesium anode. The cathode is immersed in a solution of Cu2 ions, an
Vikki [24]

Answer:

As the reaction proceeds in the given voltaic cell, the Na₂SO₄ present in the salt bridge will dissociate into Na⁺ and SO₄²⁻ ions. As the copper ions in the solution are being deposited on the copper cathode as neutral copper atoms, the solution will become more negative, therefore the Na⁺ ions in the salt bridge will migrate into the the solution in order to maintain electrical neutrality. At the anode, as the Mg metal dissolve into the solution as Mg⁺² ions, the  solution will tend to become more positive. Therefore, the SO₄²⁻ ions present in the salt bridge will migrate into the solution in order to maintain electrical neutrality.

Explanation:

A voltaic or galvanic cell is an example of an electrochemical cell.

An electrochemical cell is a device that produces an electric current from chemical reactions occuring within it.

Electrochemical cells have two electrodes; the anode and the cathode. The anode is defined as the electrode where oxidation occurs while the cathode is the electrode where reduction occurs.

The voltaic cell uses two different metal electrodes each immersed in an electrolyte solution. The two electrodes are connected to each other by means of a wire which allows the flow of electrons from the anode to the cathode. The electrolytes are connected by means of a salt bridge which is a junction that connects the electrolytic solution in the anode and cathode compartment. The salt bridge usually consists of a strong electrolyte like NaCl, KCl, Na₂SO₄, etc.

The electrolyte in the salt bridge serves two purposes: it completes the circuit by providing a path for electron flow and it maintains electrical neutrality in both solutions by allowing ions to migrate between them.

As the reaction proceeds in the given voltaic cell above, the Na₂SO₄ present in the salt bridge will dissociate into Na⁺ and SO₄²⁻ ions. As the copper ions in the solution are being deposited on the copper cathode as neutral copper atoms, the solution will become more negative, therefore the Na⁺ ions in the salt bridge will migrate into the the solution in order to maintain electrical neutrality. Also, at the anode, as the Mg metal dissolve into the solution as Mg⁺² ions, the  solution will tend to become more positive. Therefore, the SO₄²⁻ ions present in the salt bridge will migrate into the solution in order to maintain electrical neutrality.

5 0
3 years ago
Other questions:
  • what does the law of conservation of energy state? explain.please help quickly:(((( ill give u brainliest please!!
    8·1 answer
  • A gas mixture consists of 4 kg of O2, 5 kg of N2, and 7 kg of CO2. Determine (a) the mass fraction of each component, (b) the mo
    10·1 answer
  • 1.00 mL of a 250.0 µM solution of KCl is diluted to 50.0 mL. What is concentration of this solution?
    12·1 answer
  • How many miles will a person run in a 10 kilometers race
    13·1 answer
  • Explain why a sodium atom and a chlorine atom undergo an iconic bond?
    8·1 answer
  • determine the total water hardness in a 25.00 mL sample of water that require 12.45 ml of 0.01111m edta for titration
    13·1 answer
  • Which element is in the same period as chlorine (Cl) ?
    8·1 answer
  • In your reactions, you diluted the provided stock concentration of ADH for your alcohol. Calculate the actual ADH concentration
    12·1 answer
  • and the measured absorbance of a sample solution is 0.367, what is the ferroin concentration in the measured solution
    10·1 answer
  • Jean-Paul is racing in the Tour de France bicycle race. He is moving along rapidly at a speed of 15 kilometers per hour. Suddenl
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!