PLEASE HELP! FREE POINTS!

2 answers:

7 0

(a)18 bags maximum. 2 posters + 3 tickets per bag.
(b) 2 posters and 3 tickets per bag. 18 x 3 tickets = 54 & 18 x 2 posters = 36

sveta [45]3 years ago

3 0

So your looking for greatest # of goodie bags A: So in this equation you are wanting to find the GCF of the numbers which I came up with is 9 36 divided by 9= 4 Then 54 divided by 9 = 6 You do this so now you can have the same number of bags for each number which would only make sense. So we are going to have 9 bags and in one bag will carry 4 tickets and 6 posters. Hope I explained this good enough and it helps :-)

You might be interested in

Point B is the midpoint of AC, and point C is the midpoint of AD. If CD=12, what is AB?

Sliva [168]

Answer: AB = 6

Step-by-step explanation:

If CD = 12 , AC also = 12

B is the midpoint of AC so one side = 6

AB is one side of AC , so AB = 6

I am not a professional, I am simply using prior knowledge!

Note- It would mean the world to me if you would mark me brainliest!

4 0

3 years ago