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Dmitrij [34]
3 years ago
6

PLEASE HELP! FREE POINTS!

Mathematics
2 answers:
Shkiper50 [21]3 years ago
7 0
(a)18 bags maximum. 2 posters + 3 tickets per bag.
(b) 2 posters and 3 tickets per bag. 18 x 3 tickets = 54 & 18 x 2 posters = 36
sveta [45]3 years ago
3 0
So your looking for greatest # of goodie bags    A: So in this equation you are wanting to find the GCF of the numbers which I came up with is 9 36 divided by 9= 4  Then 54 divided by 9 = 6  You do this so now you can have the same number of bags for each number which would only make sense.    So we are going to have 9 bags and in one bag will carry 4 tickets and 6 posters.  Hope I explained this good enough and it helps :-) 

 
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