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bixtya [17]
3 years ago
12

What would be the LCD of 1/6 & 3/8?

Mathematics
1 answer:
slega [8]3 years ago
7 0

Answer:

24

Step-by-step explanation:

Rewriting input as fractions if necessary:

1/6, 3/8

For the denominators (6, 8) the least common multiple (LCM) is 24.

LCM(6, 8)

Therefore, the least common denominator (LCD) is 24.

Calculations to rewrite the original inputs as equivalent fractions with the LCD:

1/6 = 1/6 × 4/4 = 4/24

3/8 = 3/8 × 3/3 = 9/24

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Amelie is making a recipe that uses 1 3/4 cups flour. She is making 2 1/2 times the original recipe.
elixir [45]

Answer:

She would need 4\frac{3}{8} flour to make  2\frac{1}{2} times the recipe.

Step-by-step explanation:

To make 1 recipe Amelia uses = 1 \frac{3}{4}\ cups of flour.

So, to make 2\frac{1}{2} times the recipe she would need =1 \frac{3}{4}\times 2\frac{1}{2}.

We evaluate the above mixed numbers by converting them to fraction(by multiplying denominator with whole number and adding to numerator and write as fraction of same denominator.).

=\frac{7}{4}\times \frac{5}{2}

=\frac{35}{8}

Then converting back to mixed number (by dividing the numerator by denominator and writing the quotient as the whole number and the remainder as fraction with same denominator.

\frac{35}{8}=4\frac{3}{8}

So, she would need 4\frac{3}{8} flour to make  2\frac{1}{2} times the recipe.

7 0
3 years ago
What is (2,3) and (4,5) in slope intercept form
scoundrel [369]

Answer:

\frac{5-3}{4-2}=\frac{2}{2}=2

slope = 2

Step-by-step explanation:

6 0
3 years ago
Find the area of the shaded sector. Leave your answer in terms of π.
bearhunter [10]

Answer:

d=10m

r=10/2=5m

The Area is:

(πr^{2}) /2

(π5^2) / 2

=25π/2

=12.5π

8 0
2 years ago
Read 2 more answers
What is the LCM of 13 and 26
SSSSS [86.1K]
The lest common multiple is 26. If you do multiples of each number

13:13,26
26: 26

Both of their lest common multiples would be 26
5 0
3 years ago
Read 2 more answers
Use integration by parts to find the integrals in Exercise.<br> ∫(4x-12)e-8x dx.
stepladder [879]

Answer:

e(2x^{2} -12x)-4x^{2}+C

Step-by-step explanation:

We have been given an indefinite integral as \int \left(4x-12\right)e-8x\:dx. We are asked to find the given integral.

Let us solve our given problem.

\int \left(4x-12\right)e\:dx-\int 8x\:dx

Take out constant:

e\int \left(4x-12\right)\:dx-8\int x\:dx

e(\int 4x\:dx -\int 12\right\:dx)-8\int x\:dx

e(\frac{4x^{1+1}}{2} -12x)-8*\frac{x^{1+1}}{1+1}+C

e(\frac{4x^{2}}{2} -12x)-8*\frac{x^{2}}{2}+C

e(2x^{2} -12x)-4x^{2}+C

Therefore, our required integral would be e(2x^{2} -12x)-4x^{2}+C.

5 0
2 years ago
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