Answer:
radial acceleration is 41.8 m / s²
Explanation:
The acceleration for circular motion is
a = v² / r
They also give us the X and Y position where the body falls when the rope breaks, let's write the projectile launch equations
x = vox t
y = v₀ₓ t - ½ g t2
Since the circle is horizontally the v₀ₓ is zero (v₀ₓ = 0)
x = v₀ₓ t
t = x / v₀ₓ
y = - ½ g t²
Let's replace and calculate the initial velocity on the X axis
y = - ½ g (x / vox)²
v₀ₓ = √ (g x² / 2 y)
v₀ₓ = √ [- (-9.8) 1.6² / (2 1.00)]
v₀ₓ = 3.54 m / s
This is the horizontal velocity, but since it circle is in horizontal position it is also the velocity of the body at the point of rupture.
Now we can calculate the radial acceleration
a = v² / r
a = 3.54² / 0.300
a = 41.8 m / s²
The characteristics of the sound waves allow to find the result for the wavelength is:
λ = 34.29 m
The sound wave is a longitudinal traveling wave, where the speed of the wave depends on the air temperature.
v =
where v₀ is the speed of sound for T = 0ºc v₀ = 331 m / s.
indicate that the temperature is T = 20ºC, let's find the speed of the traveling wave.
v = 331
v = 342.9 m / s
The speed of sound is related to wavelength and frequency.
v = λ f
λ =
Let's calculate
λ = 34.29 m
In conclusion using the characteristics of sound waves we can find the result for the wavelength is:
λ = 34.29 m
Learn more here: brainly.com/question/21995826
Explanation:
The ratio of the areas is the square of the ratio of the radii.
A/A = 3.16² = 9.99
The ratio of the volumes is the cube of the ratio of the radii.
V/V = 3.16³ = 31.6
Answer:
Ferromagnetism, physical phenomenon in which certain electrically uncharged materials strongly attract others. Two materials found in nature, lodestone (or magnetite, an oxide of iron, Fe3O4) and iron, have the ability to acquire such attractive powers, and they are often called natural ferromagnets.
Hope this help :)
Answer
given,
mass of ball = 5.93 kg
length of the string = 2.35 m
revolve with velocity of 4.75 m/s
acceleration due to gravity = 9.81 m/s²
T cos θ = mg
T cos θ = 
T cos θ = 58.17






T² - 56.93T - 3383.75 = 0
T = 93.22 N

θ = 51.39°