All categories

3 years ago

5.How do simple machines make work easier?(1 point)

Physics

1 answer:

bija089 [108]3 years ago

3 0

The correct answer is d

You might be interested in

a car travels east with a velocity of 80 km/h for 90 minutes how far did the car travel (show your work)

olga55 [171]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

Given terms :

velocity (v) = 80 km/h

time (t) = 90 minutes = 1.5 hour

As we know, Distance covered is equal to :

$velocity \times time$

$80 \times 1.5$

$120 \: \: km$

3 0

3 years ago

Anions are ____.

Vinil7 [7]

Answer:

the awnser is a, just did a test with that question

4 0

3 years ago

A weight lifter struggles but manages to keep a heavy barbell abovehis head. Occasionally he slips and the barbell starts to fal

shutvik [7]

A) The lifter's and the barbell's force are equal and opposite in direction
B) The lifter's force is greater than that of the barbell and in the upward direction
C) The barbell's force is greater than that of the lifter and in the downward direction

4 0

3 years ago

Read 2 more answers

If Steve throws a football 40 m and it travels for 3 seconds, what was the balls velocity?

SpyIntel [72]

Answer:

13.4 m/s^2

Explanation:

40 divided by 3 equals 13.3 repeating.

8 0

3 years ago

A paintball is shot horizontally in the positive x direction at time t after the ball is shot it is 4 cm to the right and 4 cm b

Artist 52 [7]

<u>Answer:</u>

At time 2t the paint ball is at 8 cm to the right and 16 cm to the bottom

<u>Explanation:</u>

We have equation of motion , $s= ut+\frac{1}{2} at^2$ , s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

Considering the horizontal motion of paint ball

Distance traveled during time t = 4 cm

Initial velocity = u m/s

Acceleration = 0 $m/s^2$

So $4 = u*t+\frac{1}{2} *0*t^2\\ \\ u = \frac{4}{t}$

Now at time 2t,

$S= u*2t+\frac{1}{2} *0*(2t)^2\\ \\=\frac{4}{t} *2t\\ \\ =8cm$

So horizontal distance traveled in time 2t = 8 cm to the right

Now considering the vertical motion of paint ball

Distance traveled during time t = 4 cm

Initial velocity = 0 m/s

Acceleration = -g $m/s^2$

$4=0*t-\frac{1}{2} *g*t^2\\ \\ t^2=\frac{-8}{g}$

At time 2t,

$S=0*2t-\frac{1}{2} *g*(2t)^2\\ \\ =-\frac{1}{2} *g*4*\frac{-8}{g}\\ \\ =16 cm$

So vertical distance traveled in time 2t = 16 cm to the bottom

6 0

3 years ago