Answer:
Step-by-step explanation:
Angles 153 and QRP are straight angles, and thus Angle QRP is
180 - 153, or 27 degrees.
The interior angles of the triangle must sum up to 180 degrees:
27 + (3y + 5) + (2y - 7) = 180.
combining like terms, we get:
5y - 25 = 180, or 5y = 155, or y = 31
Then Angle Q is 3(31) + 5, or 93
Angle P is 2(31) - 7, or 55, and
Angle QRP is 27 degrees (found earlier).
Answer:
1. 21x⁴+3y-35x² + 41
2. -21x⁴-3y+6x² + x
Step-by-step explanation:
When adding and subtracting polynomials , you can use the distributive property to add or subtract the coefficients of like terms.
1. The polynomial is 21x⁴ + 3y -6x² + 34
To obtain polynomial 29x² -7 , we must subtract some polynomial from it.
Let that polynomial be k.
So, 21x⁴ + 3y -6x² + 34 - k = 29x² -7
k = 21x⁴ + 3y - 6x² +34 - 29x² +7 = 21x⁴ + 3y - 35x² + 41
2. To obtain a first degree polynomial, let that polynomial be x +34
So, 21x⁴ + 3y - 6x² + 34 + K = x + 34
K = x + 34 - 21x⁴ -3y + 6x² - 34
= -21x⁴ - 3y + 6x² + x
Answer:
life changes over time?
Step-by-step explanation:
sorry if it is wrong. I havent done this yet
Answer:
1:
p-r/6=-6-(-6)/6=-6+1=<u>-</u><u>5</u>
<u>2</u><u>:</u>
<u>p-</u><u>(</u><u>m-n</u><u>)</u><u>=</u> -1-(-4-4)=-1-(-8)=-1+8=<u>7</u>
3:
(z+y)/2)3=(-5-4)/3=-9/3=<u>-</u><u>3</u>
<u>4</u><u>:</u>
m/6-n=6/6-6=1-6=<u>-</u><u>5</u>
5:
k³-h=3³-(-2)=27+2=<u>2</u><u>9</u>
6:
p-(p-(m-3))=5-(5-(4-3))=5-(5-1)=5-4=<u>1</u>
7:
(k)(k-j)+3=(5)(5-5)+3=5*0+3=<u>3</u>
8.
p²/6-q=6²/6-4=6-4=<u>2</u>
<u>9</u><u>;</u>
zx+3³=6*4+3³=24+27=<u>5</u><u>1</u><u>.</u>
<u>1</u><u>0</u><u>:</u>
<u>y</u><u>+</u><u>z</u><u>-</u><u>(</u><u>y</u><u>-</u><u>x</u><u>)</u><u>=</u>5+4-(5-2)=9-3=<u>6</u>
<u>S</u><u>o</u><u>m</u><u>e</u><u> </u><u>b</u><u>a</u><u>s</u><u>i</u><u>c</u><u> </u><u>r</u><u>u</u><u>l</u><u>e</u><u>s</u><u>:</u>
+. +. +=+
+. * +=+
+. ÷ +=+
+. - +=+
and
+. +. -=add and put sigh of greater one.
-. * +=-sigh
-÷-=+sigh
- - -=add and put - sigh
Answer:
Let Marshall's salary be
S
m
Let Jim's salary be
S
j
Let the count in years be
n
S
m
=
$
36000
+
4000
n
S
j
=
$
51000
+
1500
n
Set
S
m
=
S
j
For convenience lets drop the $ symbol
⇒
36000
+
4000
n
=
51000
+
1500
n
Subtract
1500
n
and
36000
from both sides
4000
n
−
1500
n
=
51000
−
36000
2500
n
=
15000
Divide both sides by 2500
n
=
15000
2500
=
150
25
=
6
Step-by-step explanation: