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4 years ago

How can you maintain a balance between high-risk and low-risk investments

Mathematics

2 answers:

Lemur [1.5K]4 years ago

8 0

<span>by diversifying your investments</span>

gregori [183]4 years ago

5 0

Answer:

Well the question is incomplete, the options are:

a) By diversifying your investments

b) By making only medium risk investments

c) By putting all money in savings account

The correct answer will be,

a) By diversifying your investments.

The other two options are of no use because you can not maintain a balance between high risk and low risk by just making the medium risk investment or just by putting the money in savings account, hence in order to create a balance, diversification is necessary.

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Solve the equation<br> 4-t=3(t-1)-5

STALIN [3.7K]

Answer:

t=3

Step-by-step explanation:

4-t=3t-3-5

4-t=3t-8

4=4t-8

12=4t/4

5 0

3 years ago

Read 2 more answers

What is the simplified form of 2(3x+5)-30+7x_4

Kipish [7]

Answer:

The answer is 6x+7x_4-20

Step-by-step explanation:

6 0

4 years ago

Please help me solve this LCM

hodyreva [135]

Note that

$x^2 - y^2 = (x - y) (x + y)$

and

$x^2 + 2xy + y^2 = (x + y)^2$

Then their LCM is $\boxed{x + y}$ .

7 0

2 years ago

Which of the following equations has no solution?

daser333 [38]

Answer:

B. 3x+5−4x=−(x+8)

Explanation:

3x+5−4x=−(x+8)

Step 1: Simplify both sides of the equation.

3x+5−4x=−(x+8)

3x+5+−4x=−x+−8

(3x+−4x)+(5)=−x−8

−x+5=−x−8

Step 2: Add x to both sides.

−x+5+x=−x−8+x

5=−8

Step 3: Subtract 5 from both sides.

5−5=−8−5

0=−13

So, there is no solution

Hope this Helps!

8 0

3 years ago

Read 2 more answers

You go shopping at a local department store with your friend and cousin. You buy one pair of jeans, four pairs of shorts, and tw

VashaNatasha [74]

Answer: Cost per pair of jeans = $ 20

Cost per pair of shorts = $12

Cost per shirt = $8

Step-by-step explanation:

Let x= cost per pair of jeans

y = Cost per pair of shorts

z= cost per shirt.

For you, total cost = x+4y+2z= 84

For your friend, total cost = 2x+y+3z=76

For cousin, total cost = x+2y+z= 52

Required system:

$x+4y+2z=84\ (i)\\ 2x+y+3z=76\ (ii)\\ x+2y+z=52\ (iii)$

from (i), $x=84-4y-2z$ (*)

put this in (ii) and (iii) we get

$2\left(84-4y-2z\right)+y+3z=76\\\Rightarrow\ -7y-z+168=76\ (iv)\\\\ 84-4y-2z+2y+z=52\\\Rightarrow\ -2y-z+84=52 \ (v)$

from (iv), $y=-\frac{z-92}{7}\ (vi)$

$\mathrm{Subsititute\:}y=-\frac{z-92}{7}\ \text{in}\ (v)$

$-2\left(-\frac{z-92}{7}\right)-z+84=52\\\\\Rightarrow\ -2\left(-\frac{z-92}{7}\right)-z=-32\\\\\Rightarrow\ -\frac{5z}{7}-\frac{184}{7}=-32\\\\\Rightarrow\ -5z-184=-224\\\\\Rightarrow\ -5z=-40\\\\\Rightarrow\ z=8$