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Lana71 [14]
4 years ago
13

What can happen to the downhill toe of a slump during wet weather or times when snow is melting? ANSWER The toe can turn into a

rock avalanche. The toe can stop moving because water makes the clay sticky. The toe can become an earthflow. The toe can collapse and be deposited as talus at the base of the slope. I DON'T KNOW YET
Physics
1 answer:
jek_recluse [69]4 years ago
5 0

Answer:

Option C

The toe can become an earthflow.

Explanation:

During wet weather  especially winter season when snow is melting, the downhill toe of a slump is likely to become earthflow. It's incorrect to say that the toe turns into rock avalanche neither can the toe collapse and be deposited as a talus at the base of the slope. Despite the melting ice making clay sticky, the toe can't stop due to continued mass wasting that occurs. Therefore, the right answer is option C, <u>The toe can become an earthflow</u>

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3 years ago
What do we call the potential mechanical energy stored in an object when work is performed to change its shape?
Tom [10]
C) kinetic energy :)
7 0
3 years ago
A small sculpture made of brass (rho brass = 8470 kg/m 3 ) is believed to have a secret central cavity. The weight of the sculpt
GaryK [48]

Answer:

Volume of secret cavity = 4 x 10⁻⁶m³

Explanation:

The weight of the sculpture in air is 15.76 N

Mass of the sculpture = 1.61 kg

Mass = Volume x Density

1.61 = V x 8470

Volume of brass =1.90 x 10⁻⁴ m³

When it is submerged in water, the weight is 13.86 N.

That is

  Weight of sculpture - Weight of water displaced = 13.86 N

  15.76 - Weight of water displaced = 13.86

   Weight of water displaced = 1.9 N

   Mass of water displaced = 0.194 kg

 Mass = Volume x Density

  0.194 = V x 1000

  Volume of water displaced =1.94 x 10⁻⁴ m³

Volume of secret cavity =  Volume of water displaced - Volume of brass material

Volume of secret cavity = 1.94 x 10⁻⁴-1.94 x 10⁻⁴ = 0.04x 10⁻⁴ = 4 x 10⁻⁶m³

7 0
4 years ago
A 1.2 kg block is held at rest against the spring with a force constant k= 730 N/m. Initially, the spring is compressed a distan
mariarad [96]

Answer:

d = 9.69 cm

Explanation:

given,

mass of the block = 1.2 Kg

spring force constant(k) = 730 N/m

spring is compressed = d = ?

rough patch width = 5 cm

μ_k = 0.44

work done by friction = energy lost

\mu_k mg \times x = \dfrac{1}{2}kd^2-\dfrac{1}{2}mv^2

0.44\times 1.2 \times 9.8 \times 0.05 = \dfrac{1}{2}\times 730 \times d^2-\dfrac{1}{2}\times 1.2 \times 2.3^2

3.432 = 365 d^2

d = \dfrac{3.432}{365}

d = 0.0969 m

d = 9.69 cm

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3 years ago
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Sergeeva-Olga [200]

Answer:

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Explanation:

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