Answer:
umm section 2 and 4
Explanation:
because at section 2 it starts and at section 4 it moves again and stops at 3.
Answer:
a = 0.1962 m/s^2
Explanation:
The magnitude of kinetic friction exerted is given by

Where, μ_k= coefficient of kinetic friction= 0.02 and N = reaction force = mg
Where m= mass = 30 Kg and, g is acceleration due to gravity =9.81 m/s^2
F_k=0.02×30×9.81 =5.886 N
Now, since, there is no applied force this kinetic friction force will cause acceleration of the child
⇒ ma = F_k
here, a is the acceleration
⇒30a = 5.886
⇒ a = 0.1962 m/s^2
I think it’s D................
Answer:
Explanation:
Given
Two masses
and
is released and there is tension T in the string
Suppose a is the acceleration of the system
Therefore from Diagram
For 

------1
for m_2 body

-------2
From above two Equation it is said that Tension is greater than m_1g and less than m_2g
