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3 years ago

The ends of a bar magnet are called _____. poles domains fields currents

Physics

2 answers:

kotegsom [21]3 years ago

4 0

the correct answer is A: poles

Leto [7]3 years ago

3 0

The ends of a bar magnet are called poles. It has a north pole and a south pole. To magnet two things, the poles must be linked oppositely. North to south and south to north.

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(8%) Problem 3: Sound in water travels at a velocity governed by the relation v = √(B/rho) where B is the bulk modulus and rho i

Fittoniya [83]

Answer:

the time required for the sound to travel between the whales 0.66 S.

Explanation:

As given in the problem, the velocity of sound wave ( $v$ ) is governed by the equation

$v = \sqrt{\dfrac{B}{\rho}}$

Given, $B = 2.38 \times 10^{9} Pa$ and $\rho = 1046 Kg m^{-3}$

So for salt water, the velocity of sound wave ( $v_{s}$ ) can be written as

$v_{s} = \sqrt{\dfrac{2.38 \times 10^{9}}{1046}} ms^{-1} = 1.508 \times 10^{3} ms^{-1}$

As the whales are d = 1 Km or 1000 m apart from each other, so the time ( $t$ ) required for the sound wave to travel this distance is given by

$t = \dfrac{d}{v_{s}} = \dfrac{1000 m}{1.508 \times 10^{3}} = 0.66 s$

5 0

3 years ago

claculate the pressure exerted by the water on the bottom of a deep dam of 12m from its surface .(density of water =1000kg/m sqa

Rudiy27

Explanation:

We know that,

$hydrostatic \: pressure (p) = \alpha hg$

Where,

$\alpha = density \: of \: water \: = 1000$

h = Height at which pressure is to be calculated

$p = 1000 \times 12 \times 9.8 = 117600 \:$

8 0

3 years ago

1) if you could eliminate one item from your diet to improve your heath, what would it be?

Makovka662 [10]

Answer:

Rice

Explanation:

Because I can't control eating lots of rice

3 0

3 years ago

Read 2 more answers

A child and sled with a combined mass of 58.0 kg slide down a frictionless slope. If the sled starts from rest and has a speed o

erma4kov [3.2K]

Answer:

The height is $h = 0.5224 \ m$

Explanation:

From the question we are told that

The combined mass of the child and the sled is $m = 58.0 \ kg$

The speed of the sled is $u = 3.20 \ m/s$

Generally applying SOHCAHTOA on the slope which the combined mass is down from

Here the length of the slope(L) where the combined mass slides through is the hypotenuses

while the height(h) of the height of the slope is the opposite

Hence from SOHCAHTOA

$sin (\theta) = \frac{h}{L}$

=> $Lsin(\theta) = h$

Generally from the kinematic equation we have that

$v^2 = u^2 + 2aL$

Here the u is the initial velocity of the combined mass which is zero since it started from rest

and a is the acceleration of the combined mass which is mathematically evaluated as

$a = g * sin (\theta )$

$v^2 = u^2 + 2 * g * sin (\theta )L$

=> $2Lsin(\theta ) = \frac{v^2 - u^2 }{g}$

=> $h = \frac{ v^2 - u^2}{2g}$

=> $h = \frac{ 3.20^2 - 0^2}{2 * 9.8 }$

=> $h = 0.5224 \ m$

6 0

3 years ago

A truck with a mass of 1330 kg and moving with a speed of 15.0 m/s rear-ends a 805 kg car stopped at an intersection. The collis

Dovator [93]

Answer:

The Speed of the vehicles is 9.34m/s

Explanation:

For an elastic collision the two bodies move with similar velocities after collision

Given

M1=1330kg

V1=15m/s

M2=805kg

V2=0(the car is parked on neutral)

The formula is

M1V1+M2V2=(M1+M2)V

1330*15+805*0=(1330+805)V

19950+0=2135V

2135V=19950

divide both sides by 2135

V=19950/2135

V=9.34m/s

8 0

3 years ago