(a) The work done in moving the unit charge from point C to A is 7.62 x 10⁻³ J.
(b) The work done in moving the unit charge from point D to B is 7.62 x 10⁻³ J.
<h3>
Work done in moving the charge from C to A</h3>
W = Fd
W = Kq²/d
- from 0 origin to C, d = √(5² + 5²) = 7.07 m
- from 0 origin to A, d = 5 m
W(C to A) = W(0 to C) + W(0 to A)
<h3>
Work done in moving the charge from D to B</h3>
- from 0 origin to D, d = √(5² + 5²) = 7.07 m
- from 0 origin to B, d = 5 m
W(D to B) = W(0 to D) + W(0 to B)
W(D to B) = 7.62 x 10⁻³ J
Learn more about work done here: brainly.com/question/25573309
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Answer:
a) 20.29N
b) 19.43N
c) 15N
Explanation:
To find the magnitude of the resultant vectors you first calculate the components of the vector for the angle in between them, next, you sum the x and y component, and finally, you calculate the magnitude.
In all these calculations you can asume that one of the vectors coincides with the x-axis.
a)
b)
c)
Answer:
ΔS = - k ln (3)
Explanation:
Using the Boltzmann's expression of entropy, we have;
S = k ln Ω
Where;
S = Entropy
Ω = Multiplicity
From the question, the configuration of the molecules in a gas changes so that the multiplicity is reduced to one-third its previous value. This also causes a change in the entropy of the gas as follows;
ΔS = k ln (ΔΩ)
ΔS = kln(Ω₂) - kln(Ω₁)
ΔS = kln(Ω₂ / Ω₁) -------------(i)
Where;
Ω₂ = Final/Current value of the multiplicity
Ω₁ = Initial/Previous value of the multiplicity
Ω₂ = 
Ω₁ [since the multiplicity is reduced to one-third of the previous value]
Substitute these values into equation (i) as follows;
ΔS = k ln ( Ω₁ / Ω₁)
ΔS = k ln ()
ΔS = k ln (3⁻¹)
ΔS = - k ln (3)
Therefore, the entropy changes by - k ln (3)
Answer: 1 to 8
The Volcanic Explosivity Index (VEI) is a measure of the explosiveness of volcanic eruptions. It was devised by Chris Newhall of the United States Geological Survey and Stephen Self at the University of Hawaii in 1982. The index is based on a scale of 1 to 8, 1 being very small, and 8 being huge and very rare.
Explanation:
Inclined planes increase the speed of objects going down it. draw two pictures- a slower object going down a regular platform and a speedier object zooming down an inclined plane.
