All categories

3 years ago

What is not a reason correlations are useful?

Physics

2 answers:

bearhunter [10]3 years ago

8 0

I believe it is Correlations allow you to determine causes.

Vikki [24]3 years ago

4 0

<span>Correlations allow you to make inferences.</span>

You might be interested in

Arsine, ash3 is a highly toxic compound used in the electronics industry for the production of semiconductors. its vapor pressur

Natalka [10]

Answer: a. 17.7 KJ/Mol

b. T=210K

Explanation:

Arsine, ash3 is a highly toxic compound used in the electronics industry for the production of semiconductors. its vapor pressure is 35 torr at – 111.95°c and 253 torr at – 83.6°c. using these data calculate.

the question isnt completely originally, but we could look at the likely derivation from the questions

(a) the standard enthalpy of vaporization

using the clausius clapeyron equation

In (PT1vap / PT2vap) = delta H (vap) / R ( (1/T1) - (1/T2) )

In (35Torr/253Torr) = delta H (vap) / 8.3145 ( (1/189.55) - (1/161.2) )

Therefore, Delta H (vap) = 17.7 KJ/Mol

b. Also the boiling point

What is the normal boiling point of arsine?

At the boiling point Pvap = atmospheric pressure = 1 atm=760 torr

substitution into the equation as stated in question 1

ln(760/253)=17700/8.314(1/189.55-1/T)

T=210K

5 0

3 years ago

A 1,450 kg car drives toward a 60 kg shopping cart that has a velocity of -1.2 m/s toward the car. The two objects collide, givi

Y_Kistochka [10]

Answer:

A) v₁ = 5.66 [m/s]

Explanation:

To solve this problem we must use the definition of linear momentum conservation, which tells us that momentum is conservation before and after a collision.

The linear momentum is equal to the mass by the product of the Velocity.

P = m*v

where:

P = lineal momentum [kg*m/s]

m = mass [kg]

v = velocity [m/s]

Now, to the right side of the equal sign will take the linear momentum before the collision and to the left side of the equal sign as after the collision.

Pbefore = Pafter

(m₁*v₁) - (m₂*v₂) = (m₁*v₃) + (m₂*v₄)

where:

m₁ = mass of the car = 1450 [kg]

v₁ = velocity of the car before the collision [m/s]

m₂ = mass of the shopping cart = 60 [kg]

v₂ = velocity of the shopping cart before the collision = -1.2 [m/s]

v₃ = velocity of the car after the collision = 5.13 [m/s]

v₄ = velocity of the shopping cart after the collision = 11.75 [m/s]

Now replacing:

(1450*v₁) - (60*1.2) = (1450*5.13) + (60*11.75)

1450*v₁ - 72 = 7438.5 + 705

1450*v₁ = 7438.5 + 705 + 72

1450*v₁ = 8215.5

v₁ = 5.66 [m/s]

4 0

3 years ago

Read 2 more answers

which of the following statements is correct when describing the forces at work on a bridge a. wires are in tension B. large pos

stiv31 [10]

Answer:

All the statements are true

Explanation:

A) Wires are in tension.

It is true because the loads exerted on the bridge are taken by each of the cables of the bridge. these cables transmit the force to the pillars or columns of the bridge. (check the image 01)

B) Large posts are in compression.

It is true each of the loads of the cables is tension, are transmitted to the columns of the bridge, in this way the balance will be maintained (check the image 01)

C) The bridge deck is both in tension and compression.

Yes it is true, the superior part of the deck will be in compression and the inferior part will be in tension, this can be seen in the image 02

8 0

3 years ago

A water rocket uses an amount of water and pressurized air to send a plastic rocket several feet into the air. As the water and

Ilya [14]

Answer:

For every action there is an equal and opposite reaction.

Explanation:

im doing the same one lol

6 0

3 years ago

A proton moves perpendicular to a uniform magnetic field B with arrow at a speed of 2.40 107 m/s and experiences an acceleration

noname [10]

Answer:

0.00956770833 T

Explanation:

q = Charge of electron = $1.6\times 10^{-19}\ C$

m = Mass of proton = $1.67\times 10^{-27}\ kg$

a = Acceleration = $2.2\times 10^{13}\ m/s^2$

v = Velocity = $2.4\times 10^{7}\ m/s$

Magnetic field is given by

$B=\dfrac{ma}{qv}\\\Rightarrow B=\dfrac{1.67\times 10^{-27}\times 2.2\times 10^{13}}{1.6\times 10^{-19}\times 2.4\times 10^{7}}\\\Rightarrow B=0.00956770833\ T$

The magnetic field is 0.00956770833 T

4 0

3 years ago