Answer:
Not possible, if we talk about real pyramids
Explanation:
There is no image shown in the question statement. However if we talk about the pyramids as we find them in Egypt, we cannot get a stable inverted pyramid because of the difficulty in terms of balancing it from its centre of mass. In theory one might balance the forces, but in actual, to balance all the load of the structure just on a point is extremely difficult.
However, the term inverted pyramid can be found in ecological system and also used as metaphors in English literature
less dense material comes up. glycerin dencity= 37.8 / 30
syrup density = 80 / 60 so glycerin is less dense and comes up
Answer:
0.0005217 m/s or 5.217×10⁻⁴ m/s
Explanation:
Speed: This can be defined as the ratio of the distance covered by a body to the time taken to cover that distance. The S.I unit of speed is m/s. Speed is a scalar quantity, because it can only be represented by magnitude only.
Mathematically, speed is expressed as
S = d/t ......................................................... Equation 1
Where S = speed, d = total distance, t = time taken to cover the distance
Given: d = 120 mm = (120/1000) m = 0.12 m, t = 230 s.
Substituting into equation 1
S = 0.12/230
S = 0.0005217 m/s
Hence the speed of the security guard = 0.0005217 m/s or 5.217×10⁻⁴ m/s
Answer:
Δx = distance between central bright fringe and first bright fringe = 19.85 x 10⁻⁴ m = 1.985 mm
distance between central bright fringe and second dark fringe = 2.978 mm
Explanation:
We have the following data:
λ = wavelength of light = 641 nm = 6.41 x 10⁷ m
L = Distance of Screen from slits = 3.19 m
d = slit separation = 1.03 mm = 1.03 x 10⁻³ m
Δx = distance between consecutive bright fringes = fringe spacing = ?
Using formula:
<u>Δx = distance between central bright fringe and first bright fringe = 19.85 x 10⁻⁴ m = 1.985 mm</u>
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distance between central bright fringe and second dark fringe = 1.5Δx
distance between central bright fringe and second dark fringe = (1.5)(1.985 mm)
<u>distance between central bright fringe and second dark fringe = 2.978 mm</u>
