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lbvjy [14]
3 years ago
7

How do simple machines make it easier to move an object?

Physics
1 answer:
natima [27]3 years ago
5 0

Answer:

by Multiply Force,change direction and speed multiply

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A kayaker paddles at 4.0 m/s in a direction 30° south of west. He then turns and paddles at 3.7 m/s in a direction 20° west of s
vichka [17]

<u>Answer:</u>

  Magnitude of resultant velocity of kayaker to the nearest tenth = 10 m/s

  Direction of resultant velocity of kayaker  =  49.32⁰ South of west.

<u>Explanation:</u>

 Let east represents positive x- axis and north represent positive y - axis. Horizontal component is i and vertical component is j.

  First kayaker paddles at 4.0 m/s in a direction 30° south of west, kayaker paddles at 4.0 m/s in a direction 210° anticlockwise from positive horizontal axis.

  So velocity of kayaker = 4 cos 210 i + 4 sin 210 j = -3.46 i - 2 j

  He then turns and paddles at 3.7 m/s in a direction 20° west of south, kayaker paddles at 3.7 m/s in a direction 250° anticlockwise from positive horizontal axis.

   So that velocity = -1.27 i - 3.48 j

  So resultant velocity of kayaker = -3.46 i - 2 j +(-1.27 i - 3.48 j) = -4.71 i - 5.48 j

  Magnitude of resultant velocity of kayaker = \sqrt{(-4.71)^2+(-5.48)^2} = 7.23 m/s

 Magnitude of resultant velocity of kayaker to the nearest tenth = 10 m/s

  Direction of resultant positive horizontal axis, θ = tan⁻¹(-5.48/-4.71) = 229.32⁰ = 49.32⁰ South of west.

6 0
3 years ago
Read 2 more answers
You just landed a job as an assistant to an electrician who is working on a building site. He is making use of long single-condu
Anit [1.1K]

Answer:

R/l = 0.25925 Ω / m

Explanation:

Ohm's law says that the potential difference is proportional to the product of the resistance by the current

         V = I R

         R = V / I

In this case, since we have two lengths, we can have two lengths, we can find the resistance for each

         L = 5 m

         R = 7.70 / 5.47

         R = 1,408 Ω

         L = 10 m

         R = 7.70 / 3.25

         R = 2,369 Ω

We can make a direct proportions rule (rule of three) to find the resistance per unit length

For L = 5 m

         R/l = 1,408 / 5

         R/l = 0.2816 Ω / m

For L = 10 m

        R/l = 2,369/10

        R/l = 0.2369 Ω / m

We can see that the value is similar that differs from the second decimal place, in this case the value for the longer re wire is more accurate because it has a lower joule effect.

One way also to find the average value

       R/l = (0.2816 + 0.2369) / 2

       R/l = 0.25925 Ω / m

3 0
3 years ago
Read 2 more answers
A protostar's radius decreases by a factor of 100 and its surface temperature increases by a factor of two before it becomes a m
Sliva [168]

Answer:

L_f = K (\frac{r}{100})^2 * (2T)^4

L_f = K \frac{r^2}{10000} * 16 T^4

L_f = \frac{16}{10000} k r^2 T^4 = \frac{1}{625} k r^2 T^4

L_f = \frac{1}{625} L_i

So then we see that the final luminosity decrease by a factor of 625 so then the correct answer for this case would be:

B. Decreases by a factor of 625

Explanation:

For this case we can use the formula of luminosity in terms of the radius and the temperature given by:

L_i = K r^2 T^4

Where L_i = initial luminosity, r= radius and T = temperature.

We know that we decrease the radius by a factor of 100 and the temperature increases by a factor of 2 so then the new luminosity would be:

L_f = K (\frac{r}{100})^2 * (2T)^4

L_f = K \frac{r^2}{10000} * 16 T^4

L_f = \frac{16}{10000} k r^2 T^4 = \frac{1}{625} k r^2 T^4

L_f = \frac{1}{625} L_i

So then we see that the final luminosity decrease by a factor of 625 so then the correct answer for this case would be:

B. Decreases by a factor of 625

6 0
3 years ago
________ cable is NOT subject to electromagnetic interference or radio frequency interference. Polycarbonate Twisted-pair Coaxia
malfutka [58]

Answer:

The correct option is: d. Fiber-optic

Explanation:

A fiber-optic cables or an optical-fiber cable is a cable that is composed of a bundle of optical fibers. These cables are used for transmitting information or digital signals over long distances.

Each optical fiber in an optical-fiber cable is individually coated with a protective plastic cover and contained in a protective tube. Therefore, an optical-fiber cable is not affected by any electromagnetic interference or radio frequency interference.

5 0
3 years ago
If a beaker of water is placed under a broiler so that the heating coil is above the beaker. It is observed that only the surfac
bija089 [108]

Answer:

a

Explanation:

The most reasonable conclusion of the above phenomenon is that water is a poor conductor of heat. Basically water is an insulator. The heat from surface to the bottom of the beaker will take a lot of time. Moreover, no convection current is formed so, heat might not even reach the bottom surface. Hydrogen bonding also play a vital role in determining the thermal properties of water.

hence option A is correct

5 0
3 years ago
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