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Tatiana [17]
2 years ago
7

Ejbsjca bdsj dbcsc j ecsabkfskbj jcbaskjbb

Physics
1 answer:
alexandr1967 [171]2 years ago
3 0

Sorry but I can't help you cuz the words you use makes no sens if you are going to ask a question pls do and dont joke around about it thank you very much and have a great day! ^^

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Which of the following non-metals is used as a lubricant in powdered form?
blondinia [14]

Answer:

Graphite.

Explanation:

Graphite:<em> "a gray crystalline allotropic form of carbon which occurs as a mineral in some rocks and can be made from coke. It is used as a solid lubricant, in pencils, and as a moderator in nuclear reactors."</em>

5 0
3 years ago
A 4.5 g coin sliding to the right at 23.8 cm/s makes an elastic head-on collision with a 13.5 g coin that is initially at rest.
Airida [17]

Answer:

a) v = 11.9\times 10^{-2}\,\frac{m}{s} \,(11.9\,\frac{cm}{s} ), b) \Delta K = 9.559\times 10^{-5}\,J

Explanation:

a) The final velocity of the 13.5 g coin is found by the Principle of Momentum Conservation:

(4.5\times 10^{-3}\,kg)\cdot (23.8\times 10^{-2}\,\frac{m}{s} )+(13.5\times 10^{-3}\,kg})\cdot (0\,\frac{m}{s} ) = (4.5\times 10^{-3}\,kg)\cdot (-11.9\times 10^{-2}\,\frac{m}{s} )+(13.5\times 10^{-3}\,kg})\cdot v

The final velocity is:

v = 11.9\times 10^{-2}\,\frac{m}{s} \,(11.9\,\frac{cm}{s} )

b) The change in the kinetic energy of the 13.5 g coin is:

\Delta K = \frac{1}{2}\cdot (13.5\times 10^{-3}\,kg)\cdot \left[(11.9\times 10^{-2}\,\frac{m}{s} )^{2}-(0\,\frac{m}{s} )^{2}\right]

\Delta K = 9.559\times 10^{-5}\,J

4 0
3 years ago
Read 2 more answers
Two point charges, 1.8 pC and −1.8 pC, are separated by 7 µm. What is the dipole moment of this pair of charges?
Salsk061 [2.6K]

Answer: 12,600,000Cm

Explanation:

From the data's;

Charges(q) = 1.8 PC equal to 1.8 x 10^¹²C

Distance = 7 micrometer, is equal to 0.0000070m

From the equation of electric dipole moment, p= q x d, where q= charge, d=distance and p is the dipole moment.

Then we have 1.8x10^¹² x 0.0000070= 12,600,000Cm

NB: The charges are identical.

3 0
3 years ago
How many aluminium ions are needed to cross an ammeter if you want a current of 3A?
Reptile [31]
Assuming that the time needed to cross the ammeter is 1 hour or 3600s, then using coloumb's law,
I x t = F x m / (eq. wt)

Using the given values and formula:
3 x 3600 = 96500 x m / (27/3)

Solving for m,
m = 1.007 g of Al3+
6 0
4 years ago
Systems in nature tend to undergo changes toward___? Explain your answer.
IrinaK [193]

The correct answer is option 2. Systems, by nature, tend to undergo changes toward higher entropy and lower energy since this is the state where they are most stable. Entropy is the degree of disorderliness of a substance. Systems tend to go to higher disorder since systems always tend to change which can be linked to disorder and is inevitable.

6 0
3 years ago
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