Answer:
The straight, diagonal line represent a tangent line
Explanation:
As the shown straight diagonal line represented in the figure just goes by touching a part or points on the curve, this line will be termed as tangent line. A secant line is the one which joins two points on the curve in the inward side. But in this case, the line is touching the outward points of the curve. Also the line is sliding through the curve in outward points. So this kind of line touching some points on any curve is termed as tangential line or slope of that curve.
Answer:
This question is hard I will edit my answer when I find the answer
Explanation:
Answer:
40.5 N
Explanation:
second law of newto says : F = ma
F= 4.5 × 9 = 40.5 N
The center of gravity of the homogeneous semicircular rod bent is 2R/π .
We need to know about center of mass to solve this problem. Center of mass can be determined as
Xm = ∫x . dm / ∫dm
Assume that
dm = λ .dl
with radius R and angle θ we get
dm = λ . dl
dm = λ . R dθ
Hence the (∫x . dm) from 0 to π is
∫x . dm = ∫ λ . R dθ
∫x . dm = ∫ R.sinθ. λ. R dθ
∫x . dm = λ. R² ∫sinθ dθ
∫x . dm = λ. R² [-cosθ]
with limit of integral from 0 to π we get [-cosθ]
∫x . dm = λ. R² [- (-1) - (-1)]
∫x . dm = 2λ . R² = 2 . (0.5) . R² = R²
The (∫dm) from 0 to π is
∫dm = ∫λ . R dθ
∫dm = λ . R ∫dθ
∫dm = λ . R ∫dθ
∫dm = λ . R [θ]
with limit of integral from 0 to π we get [θ]
∫dm = λ . R . π = 0.5 Rπ
Hence, the center of mass is
Xm = ∫x . dm / ∫dm
Xm = R² / (0.5 Rπ)
Xm = 2R/π
where R is radius of the semicircular rod bent.
Find more on center of mass at: brainly.com/question/13499822
#SPJ4
