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7nadin3 [17]
4 years ago
6

How can you tell a density of a reaction?

Chemistry
1 answer:
Lemur [1.5K]4 years ago
3 0
I don't really understand your question but I hope this helps. <span>density = mass divided my volume. 
</span>

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When potassium metal is placed in water, a large amount of energy is released as potassium hydroxide and hydrogen gas are produc
sergeinik [125]
It’s a redox reaction since k has been oxidised and h has been reduced. i doubt it’s a combustion rxn since the end products should be C0₂ and H₂0
5 0
3 years ago
Two molecules that can cross a lipid bilayer without help from membrane proteins are o2 and co2. what property allows this to oc
Dennis_Churaev [7]
Two molecules that can cross a lipid bilayer without help from membrane proteins are oxygen and carbon dioxide. The property that allows this to happen is that both oxygen and carbon dioxide molecules are nonpolar which means that they can pass easily through the hydrophobic part of the membrane. The lipid bilayer is present in all cell membranes. It consists of two layers of the fat cells which are arranged into two sheets. It functions as a barrier which marks the boundaries of the cell. The inner part of a lipid bilayer is nonpolar since it is composed of the hydrophobic end of the phospholopids. 
4 0
3 years ago
What is the mass of 1.72 moles of BaSO4?
yarga [219]

Explanation:

mass = Moles * molar mass

molar mass of BaSO4 = 112+32+64= 208

= 1.72*208 = 357.76

4 0
3 years ago
What does the hydrosphere include?<br><br> Glaciers <br> Groundwater<br> Lava<br> Polar Ice
Darya [45]

Answer:

Groundwater, Glaciers, and Polar Ice.

Explanation:

3 0
3 years ago
How many moles of copper(II)sulfate are in in 5.00 L of a 2.00 M solution?
Julli [10]

Answer:

There are 10 moles of copper(II)sulfate.

Explanation:

We know that molarity is a concentration measure that expresses the moles of solute per liter of solution: in this case, being 1.30 molar, there are 1.30 moles of solute in 1 liter of solution. We solve with the following simple rule of three:

1 L solution-----2 moles of copper(II)sulfate

5 L solution----x= (5 L solution x 2 moles of copper(II)sulfate)/1 L solution

<em>x= 10 moles of copper(II)sulfate</em>

3 0
4 years ago
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