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aivan3 [116]
3 years ago
11

During science lab, Carl notices that when he adds water to his solid sample of anhydrous copper

Chemistry
1 answer:
Bond [772]3 years ago
4 0

Answer:

The dissociation of copper sulfate into ions is an exothermic chemical reaction that releases heat into the surroundings.

Explanation:

Some of the potential energy stored in the solid sample of anhydrous copper sulfate is released as heat as the sample dissolves and dissociates into ions in the water. This is due to the large lattice energy of the crystalline copper sulfate.

hope this helps

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alukav5142 [94]
I can help you! What is your question?
8 0
4 years ago
The reaction between calcium acetate and lithium phosphate forms a white precipitate (the insoluble compound calcium phosphate),
kenny6666 [7]

Hello!


The coefficient for Lithium Acetate in the balanced chemical equation is 6


Why?


This is the reaction:


(CH₃COO)₂Ca(aq) + Li₃PO₄(aq) → Ca₃(PO₄)₂(s) + CH₃COOLi(aq)


For balancing the equation, we're going to apply the Law of Conservation of Mass, which states that matter is not created nor destroyed, and the number of atoms of each element should be the same on both sides of the equation, from that, the balanced equation is:


3(CH₃COO)₂Ca(aq) + 2Li₃PO₄(aq) → Ca₃(PO₄)₂(s) + 6CH₃COOLi(aq)


Have a nice day!

3 0
4 years ago
An unknown metal cylinder has a mass of 34.3 g and a volume of 2.1 mL . What is the density of the metal in g / m * L ?​
saul85 [17]

Taking into account the definition of density, the density of the metal is 16.33 \frac{g}{mL}.

<h3>Definition of density</h3>

Density is a quantity that allows us to measure the amount of mass in a certain volume of a substance. Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:

density=\frac{mass}{volume}

From this expression it can be deduced that density is inversely proportional to volume: the smaller the volume occupied by a given mass, the higher the density.

<h3>Density of the metal in this case</h3>

In this case, you know that:

  • Mass= 34.3 g
  • Volume= 2.1 mL

Replacing in the definition of density:

density=\frac{34.3 g}{2.1 mL}

Solving:

<u><em>density= 16.33 </em></u>\frac{g}{mL}

In summary, the density of the metal is 16.33 \frac{g}{mL}.

Learn more about density:

<u>brainly.com/question/952755?referrer=searchResults</u>

<u>brainly.com/question/1462554?referrer=searchResults</u>

6 0
2 years ago
The activation barrier for the hydrolysis of sucrose into glucose and fructose is 108 kJ/mol. Part A If an enzyme increases the
emmasim [6.3K]

Answer:

The barrier has to be 34.23 kJ/mol lower when the sucrose is in the active site of the enzyme

Explanation:

From the given information:

The activation barrier for the hydrolysis of sucrose into glucose and fructose is 108 kJ/mol.

In this  same concentration for the glucose and fructose; the reaction rate can be calculated by the rate factor which can be illustrated from the Arrhenius equation;

Rate factor in the absence of catalyst:

k_1= A*e^{^{^{ \dfrac {- Ea_1}{RT}}

Rate factor in the presence of catalyst:

k_2= A*e^{^{^{ \dfrac {- Ea_2}{RT}}

Assuming the catalyzed reaction and the uncatalyzed reaction are  taking place at the same temperature :

Then;

the ratio of the rate factors can be expressed as:

\dfrac{k_2}{k_1}={  \dfrac {e^{ \dfrac {- Ea_2}{RT} }} { e^{ \dfrac {- Ea_1}{RT} }}

\dfrac{k_2}{k_1}={  \dfrac {e^{[  Ea_1 - Ea_2 ] }}{RT} }}

Thus;

Ea_1-Ea_2 = RT In \dfrac{k_2}{k_1}

Let say the assumed temperature = 25° C

= (25+ 273)K

= 298 K

Then ;

Ea_1-Ea_2 = 8.314 \  J/mol/K * 298 \ K *  In (10^6)

Ea_1-Ea_2 = 34228.92 \ J/mol

\mathbf{Ea_1-Ea_2 = 34.23 \ kJ/mol}

The barrier has to be 34.23 kJ/mol lower when the sucrose is in the active site of the enzyme

8 0
3 years ago
Complex ___ of ETC, which mediates transfer of electrons from succinate (FADH2) to UQ, is not a proton pump.
aleksandrvk [35]

Answer:

Complex II

Explanation:

Complex II does not directly pump protons but rather sends two protons on to Complex III in the form of the reduced UQ known as ubiquinol.

Thus, the correct answer is Complex II

5 0
3 years ago
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