Question

A bag contains a mixture of almonds, walnuts, and cashews. There is an equal quantity of each nut. If a nut is chosen randomly out of the bag, what is the probability that the nut is either an almond, a walnut, or a cashew? Round answer to the nearest thousandth. A. 0.333 B. 0.667 C. 0.750 D. 1

Answer 1

The answer is D.1

If all the nuts in the bag are of equal quantity to one another then the chance of pulling a nut out of that category is the same as the other which is 1

Answer 2

Answer:

Option D. 1

Step-by-step explanation:

A bag contains a mixture of almonds, walnuts and cashews in an equal quantity of each nut.

If a nut is chosen randomly out of the bag,

Each have the same probability, that the nut is either an almond, a walnut or a cashew.

P (Almond) = $\frac{1}{3}$

P (Walnut) =  $\frac{1}{3}$

P (Cashew) = $\frac{1}{3}$

P (almond or walnut or Cashew) = P(almond) + P(walnut) + P(cashew)

P = $\frac{1}{3}+\frac{1}{3}+\frac{1}{3}$ = $\frac{3}{3}$

P = 1

The probability that a nut is either an almond, a walnut or a cashew is 1.