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Ganezh [65]
3 years ago
9

A bag contains a mixture of almonds, walnuts, and cashews. There is an equal quantity of each nut. If a nut is chosen randomly o

ut of the bag, what is the probability that the nut is either an almond, a walnut, or a cashew? Round answer to the nearest thousandth. A. 0.333 B. 0.667 C. 0.750 D. 1
Mathematics
2 answers:
OLEGan [10]3 years ago
7 0
The answer is D.1

If all the nuts in the bag are of equal quantity to one another then the chance of pulling a nut out of that category is the same as the other which is 1
nata0808 [166]3 years ago
7 0

Answer:

Option D. 1

Step-by-step explanation:

A bag contains a mixture of almonds, walnuts and cashews in an equal quantity of each nut.

If a nut is chosen randomly out of the bag,

Each have the same probability, that the nut is either an almond, a walnut or a cashew.

P (Almond) = \frac{1}{3}

P (Walnut) =  \frac{1}{3}

P (Cashew) = \frac{1}{3}

P (almond or walnut or Cashew) = P(almond) + P(walnut) + P(cashew)

P = \frac{1}{3}+\frac{1}{3}+\frac{1}{3} = \frac{3}{3}

P = 1

The probability that a nut is either an almond, a walnut or a cashew is 1.

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Hi who can help me do this 2quetion,I will mark brainlest ​
hodyreva [135]

Step-by-step explanation:

8.  log_{10}(2.15)   = 0.332 \: then \:   log_{10}(21500)   = ..... \\  log(21500)  =  log(2.15 \times 10000)  \\   =  log(2.15)  +  log(10000)  \\   = log_{10}(2.15)  +  log_{10}( {10}^{4} )  \\  = 0.332 + 4 log_{10}(10)  \\  = 0.332 + 4(1) \\  log_{10}(21500)  = 4.332

9. log(2)=a, log(3)=b, then log(36)=______

log(36) = log(6*6) = log(6) + log(6)

log(36)= log(6) + log(6)

log(36) = log(3*2) + log(3*2)

log(36) = (log(3) + log(2)) + (log(3) + log(2))

log(36) = (a + b) + (b + a)

log(36) = a + b + b + a

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5 0
2 years ago
Read 2 more answers
If f(x)=x+7 and g(x)=2x-3 what is (f-g)(x)
aalyn [17]

Answer:

-x + 10

Step-by-step explanation:

(x + 7) - (2x-3)

x + 7 - 2x - 3

x - 2x

-x + 7 + 3

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4 0
2 years ago
Forces of 9 lbs and 13 lbs act at a 38º angle to each other. Find the magnitude of the resultant force and the angle that the re
fiasKO [112]

Answer: R=20.84\ lb\quad 22.57^{\circ},15.43^{\circ}

Step-by-step explanation:

Given

Two forces of 9 and 13 lbs acts 38^{\circ} angle to each other

The resultant of the two forces is given by

\Rightarrow R=\sqrt{a^2+b^2+2ab\cos \theta}

Insert the values

\Rightarrow R=\sqrt{9^2+13^2+2(9)(13)\cos 38^{\circ}}\\\Rightarrow R=\sqrt{81+169+184.394}\\\Rightarrow R=\sqrt{434.394}\\\Rightarrow R=20.84\ lb

Resultant makes an angle of

\Rightarrow \alpha=\tan^{-1}\left( \dfrac{b\sin \theta}{a+b\cos \theta}\right)\\\\\text{Considering 9 lb force along the x-axis}\\\\\Rightarrow \alpha =\tan^{-1}\left( \dfrac{13\sin 38^{\circ}}{9+13\cos 38^{\circ}}\right)\\\\\Rightarrow \alpha =\tan^{-1}(\dfrac{8}{19.244})\\\\\Rightarrow \alpha=22.57^{\circ}

So, the resultant makes an angle of 22.57^{\circ} with 9 lb force

Angle made with 13 lb force is 38^{\circ}-22.57^{\circ}=15.43^{\circ}

7 0
3 years ago
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The endpoints of `bar(EF)` are E(xE , yE) and F(xF , yF). What are the coordinates of the midpoint of `bar(EF)`?
Hoochie [10]

For a better understanding of the solution provided here please find the diagram attached.

Please note that in coordinate geometry, the coordinates of the midpoint of a line segment is always the average of the coordinates of the endpoints of that line segment.

Thus, if, for example, the end coordinates of a line segment are (x_{1}, y_1) and (x_2, y_2) then the coordinates of the midpoint of this line segment will be the average of the coordinates of the two endpoints and thus, it will be:

(\frac{(x_1+x_2)}{2}, \frac{(y_1+y_2)}{2})

Thus for our question the endpoints are (x_E, y_E) and (x_F, y_F) and hence the midpoint will be:

(x_M, y_M)=(\frac{(x_E+x_F)}{2}, \frac{(y_E+y_F)}{2})

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6 0
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aksik [14]
Let x = the number of hours Eva needs to complete the job
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x = 6
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6 0
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