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4 years ago

9

1) What happened around 10,000 years ago that changed the way many humans live?

2 answers:

ziro4ka [17]4 years ago

6 0

Answer:

c

Explanation:

hope everything is good!!

love history [14]4 years ago

3 0

The answer is C

Hope it helps ;)

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Dmitri Mendeleev and Henry Moseley developed their periodic tables about forty years apart. During that time, many discoveries i

Sindrei [870]

Answer:

The first one I think

Explanation:

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4 years ago

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How many cubic feet of air at standard conditions 1.00 atm are required to inflate a bicycle tote of .50 cu. Ft. To a pressure o

Alexeev081 [22]

As I am reading the problem, I see they gave you two pressures, one volume and they are asking for another volume. this should give you a hint that you need to use the following formula.

P1V1= P2V2

P1= 1.00 atm
V1= 0.50 ft³
P2= 3.00 atm
V2= ?

Now we plug the values

(1.00 x 0.50)= (3.00 x V2)

V2= 0.17 ft³

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3 years ago

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lidiya [134]

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3 years ago

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Given the following information: Mass of proton = 1.00728 amu Mass of neutron = 1.00866 amu Mass of electron = 5.486 × 10^-4 amu

lesya692 [45]

<u>Answer:</u> The nuclear binding energy of the given element is $2.938\times 10^{12}J/mol$

<u>Explanation:</u>

For the given element $_3^6\textrm{Li}$

Number of protons = 3

Number of neutrons = (6 - 3) = 3

We are given:

$m_p=1.00728amu\\m_n=1.00866amu\\A=6.015126amu$

M = mass of nucleus = $(n_p\times m_p)+(n_n\times m_n)$

$M=[(3\times 1.00728)+(3\times 1.00866)]=6.04782amu$

Calculating mass defect of the nucleus:

$\Delta m=M-A\\\Delta m=[6.04782-6.015126)]=0.032694amu=0.032694g/mol$

Converting this quantity into kg/mol, we use the conversion factor:

1 kg = 1000 g

So, $0.032694g/mol=0.032694\times 10^{-3}kg/mol$

To calculate the nuclear binding energy, we use Einstein equation, which is:

$E=\Delta mc^2$

where,

E = Nuclear binding energy = ? J/mol

$\Delta m$ = Mass defect = $0.032694\times 10^{-3}kg/mol$

c = Speed of light = $2.9979\times 10^8m/s$

Putting values in above equation, we get:

$E=0.032694\times 10^{-3}kg/mol\times (2.9979\times 10^8m/s)^2\\\\E=2.938\times 10^{12}J/mol$

Hence, the nuclear binding energy of the given element is $2.938\times 10^{12}J/mol$

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3 years ago

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masya89 [10]

I think a is the correct answer

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3 years ago