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natita [175]
3 years ago
9

Which gas has a higher rate of effusion sulfur dioxide or oxygen? why?

Chemistry
1 answer:
musickatia [10]3 years ago
4 0
The sulfer dioxide would give off a higher effusion rate because of both the sulfer and the dioxide would give off a smell

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Air at 293 K and 750 mm Hg pressure has a relative humidity of 80%. What is its percent humidity? The vapour pressure of water a
Mekhanik [1.2K]

Answer : The correct option is, (c) 79.62

Explanation :

The formula used for percent humidity is:

\text{Percent humidity}=\text{Relative humidity}\times \frac{p-p^o_v}{p-p_v}\times 100   ..........(1)

The formula used for relative humidity is:

\text{Relative humidity}=\frac{p_v}{p^o_v}       ...........(2)

where,

p_v = partial pressure of water vapor

p^o_v = vapor pressure of water

p = total pressure

First we have to calculate the partial pressure of water vapor by using equation 2.

Given:

p=750mmHg

p^o_v=17.5mmHg

Relative humidity = 80 % = 0.80

Now put all the given values in equation 2, we get:

0.80=\frac{p_v}{17.5mmHg}

p_v=14mmHg

Now we have to calculate the percent humidity by using equation 1.

\text{Percent humidity}=0.80\times \frac{750-17.5}{750-14}\times 100

\text{Percent humidity}=79.62\%

Therefore, the percent humidity is 79.62 %

4 0
3 years ago
A nitrox ii gas mixture for scuba diving contains oxygen gas at 53 atm and nitrogen gas at 94 atm . what is the total pressure,
Alina [70]

Answer: The total pressure will be 1,11,720 torr.

Explanation:

Partial pressure of nitrogen gas.p_{N_2}=53 atm=53\times 760 torr= 40,280 torr (1atm = 760 torr)

Partial pressure of oxygen gas,p_{O_2}=94 atm=94\times 760 torr=71,440 torr

Total pressure, in torrs, of the scuba gas mixture = 40280 + 71440 torr =111,720 torr

Hence , the total pressure in scuba gas mixture is 111,720 torr.

6 0
3 years ago
I NEED HELP WITH #3 pleaseeee
Anit [1.1K]

Answer:

energy level

sub energy level

electrons in the orbital

Explanation:

3 0
3 years ago
how many grams of antifreeze would be required per 500 g of water to prevent the water from feezing at a temperature of -39° C​
andrezito [222]

Answer:

333.7g of antifreeze

Explanation:

Freezing point depression in a solvent (In this case, water) occurs by the addition of a solute. The law is:

ΔT = Kf × m × i

Where:

ΔT is change in temperature (0°C - -20°C = 20°C)

Kf is freezing point depression constant (1.86°C / m)

m is molality of solution (moles solute / 0.5 kg solvent -500g water-)

i is Van't Hoff factor (1, assuming antifreeze is ethylene glycol -C₂H₄(OH)₂)

Replacing:

20°C = 1.86°C / m  × moles solute / 0.5 kg solvent × 1

5.376 = moles solute

As molar mass of ethylene glycol is 62.07g/mol:

5.376 moles × (62.07g / 1mol) = <em>333.7g of antifreeze</em>.

4 0
3 years ago
Which statement describes the motion of the sun?
balu736 [363]

different parts of the sum rotate at different rates

5 0
3 years ago
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