The answer is 2.53e-5, I unfortunately don't know how you would really show the work other than showing the division.
The ccorrect answer is C a generator tubrine
Answer:
-10778.95 J heat must be removed in order to form the ice at 15 °C.
Explanation:
Given data:
mass of steam = 25 g
Initial temperature = 118 °C
Final temperature = 15 °C
Heat released = ?
Solution:
Formula:
q = m . c . ΔT
we know that specific heat of water is 4.186 J/g.°C
ΔT = final temperature - initial temperature
ΔT = 15 °C - 118 °C
ΔT = -103 °C
now we will put the values in formula
q = m . c . ΔT
q = 25 g × 4.186 J/g.°C × -103 °C
q = -10778.95 J
so, -10778.95 J heat must be removed in order to form the ice at 15 °C.
<span>Oil and water don't mix because oil is made up of non-polar molecules while water molecules are polar in nature. Because water molecules are electrically charged, they get attracted to otherwater molecules and exclude the oil molecules. (this is from wiki)</span>
Answer:
Rb+
hope it's right:)
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