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Elina [12.6K]
3 years ago
11

4.0 moles of H2O would have what mass?

Chemistry
2 answers:
Kitty [74]3 years ago
8 0

Answer:

How many moles H2O in 1 grams? The answer is 0.055508435061792.

We assume you are converting between moles H2O and gram.

You can view more details on each measurement unit:

molecular weight of H2O or grams

This compound is also known as Water or Dihydrogen Monoxide.

The SI base unit for amount of substance is the mole.

1 mole is equal to 1 moles H2O, or 18.01528 grams.

Explanation:

gavmur [86]3 years ago
7 0

Answer:

about 18 grams mass of H2O

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As you move from left to right across a period, what happens to the atomic radil?
egoroff_w [7]

Answer:

Moving Across a Period

Moving from left to right across a period, the atomic radius decreases. The nucleus of the atom gains protons moving from left to right, increasing the positive charge of the nucleus and increasing the attractive force of the nucleus upon the electrons

4 0
3 years ago
Explain why the atomic radius decreases across a period and increases down a group ?​
andreyandreev [35.5K]

Answer:

In general, atomic radius decreases across a period and increases down a group. ... Down a group, the number of energy levels (n) increases, so there is a greater distance between the nucleus and the outermost orbital. This results in a larger atomic radius.

4 0
3 years ago
How many moles are 21.67 L of NH4CI?<br> Type your answer...
NNADVOKAT [17]

Answer:

0.967mole

Explanation:

Given parameters:

Volume of NH₄Cl  = 21.67L

Unknown:

Number of moles  = ?

Solution:

We assume that the volume was taken at standard temperature and pressure,

 Then;

  Number of moles  = \frac{volume }{22.4L}  

 Number of moles  = \frac{21.67}{22.4}   = 0.967mole

6 0
3 years ago
What is the oxidation state of each element in the species Mn(ClO4)3?
gayaneshka [121]
The oxidation state of the compound Mn (ClO4)3 is to be determined in this problem. For oxygen, the charge is 2-, the total considering its number of atoms is -24. Mn has a charge of +3. TO compute for Mn, we must achieve zero charge overall hence 3+3x-24=0 where x is the Cl charge. Cl charge, x is +7. 
7 0
3 years ago
Read 2 more answers
A sample of hydrated copper (II) sulfate (CuSO4•nH2O) is heated to 150°C and produces 103.74 g anhydrous copper (II) sulfate and
wariber [46]

Answer:

5

Explanation:

Firstly, we convert what we have to percentage compositions.

There are two parts in the molecule, the sulphate part and the water part.

The percentage compositions is as follows:

Sulphate- (103.74)/(103.74 + 58.55) × 100% = apprx 64%

The water part = 100 - 64 = 36%

Now, we divide the percentages by the molar masses.

For the CuSO4 molar mass is 64 + 32 + 4(16) = 160g/mol

For the H2O = 2(1) + 16 = 18g/mol

Now we divide the percentages by these masses

Sulphate = 64/160 = 0.4

Water = 36/18 = 2

The ratio is thus 0.4:2 = 1:5

Hence, there are 5 water molecules.

3 0
3 years ago
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