Answer:
The chance that there will be exactly 2 heads among the first five tosses and exactly 4 heads among the last 5 tosses is P=0.0488.
Step-by-step explanation:
To solve this problem we divide the tossing in two: the first 5 tosses and the last 5 tosses.
Both heads and tails have an individual probability p=0.5.
Then, both group of five tosses have the same binomial distribution: n=5, p=0.5.
The probability that k heads are in the sample is:

Then, the probability that exactly 2 heads are among the first five tosses can be calculated as:

For the last five tosses, the probability that are exactly 4 heads is:

Then, the probability that there will be exactly 2 heads among the first five tosses and exactly 4 heads among the last 5 tosses can be calculated multypling the probabilities of these two independent events:

Glass bottles =total number of bottles - numeber of bottle of plastic
gass bottles=50-19=31 bottles of glass.
percent of the bottles are glass=(number of bottles of glass*100%) / total number of bottles.
percent of the glass bottles=(31 bottles * 100%) / 50 bottles=62%
Answer: the percent of the bottles of glas is 62%
The Associative Property say that it doesn't matter how we group the numbers (i.e. which we calculate first) when we add
(a + b) + c = a + (b + c)
The Commutative Property say we can swap numbers over and still get the same answer when we add
a + b = b + a
The Distributive Property:
a(b + c) = ab + ac
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-3a + 4b + 5a + (-7b) = -3a + 5a + 4b + (-7b)
<h3>Answer: the commutative property</h3>
so from 190.1 to 201.5 is 201.5 - 190.1 = 11.4.
now, if we take 190.1 as the 100%, what is 11.4 off of it in percentage?

Answer:
I believe the answer is about 34
Step-by-step explanation: