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3 years ago

Given the graph below, which of the following represents the domain of the function?

Mathematics

1 answer:

krek1111 [17]3 years ago

7 0

Do you have the graph?

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What is the value of y that satisfies the

Allisa [31]

Y=4
3y/4=12/3
y=4 3/3=1
12/3=4 so y=4

3 0

3 years ago

Please help I'm giving 11 pt

FrozenT [24]

They put the parabola in vertex form for us so we can just read off the answer.

y = a(x-p)² + q

has a vertex at (p,q)

Answer: (20.41, 2065.82)

7 0

3 years ago

Read 2 more answers

Ira Lisetskai [31]

Answer:

Y = 120

Step-by-step explanation:

Y & X

Y = K(X) where K is constant

given: 72 = K(6)

i.e K = 12

Y = 12(x) is the relationship

Y = 12(10)

Y = 120

7 0

3 years ago

I tried to figure it out but i can't. i need to show the work and i don't know how to do it.

Andreas93 [3]

Integration Formula:

$\int\limits {x}^{n} \, dx =\frac{x^{n+1}}{n+1} + C$

Integrate each term:

$\int\ {x^{2}} \, dx = \frac{x^{3}}{3}$

$\int\ {x} \, dx =\frac{x^2}{2}$

$\int\ {5} \, dx = 5x$

$\int\ {x} \, dx =\frac{x^2}{2}$

$\int\ {2} \, dx = 2x$

Altogether this becomes:

$\frac{\frac{x^3}{3} - \frac{x^2}{2}-5x }{ \frac{x^2}{2}+2x}$

Your limits are 1 and 2. Substitute both numbers into the equation and minus them from each other.

x = 2:

$\frac{\frac{2^3}{3} - \frac{2^2}{2}-5(2) }{ \frac{2^2}{2}+2(2)}$

x = 1:

$[tex]\frac{\frac{1}{3} - \frac{1}{2}-5 }{ \frac{1}{2}+2}$ [/tex]

x = 2:

$\frac{\frac{8}{3} - \frac{4}{2}-10 }{ \frac{4}{2}+4}$

x = 1: $\frac{\frac{8}{3} - 2-10 }{ 2+4}$

-1.212317928

Now convert all the answers to integers and see which one matches -1.212317928:

Because it's a negative number, we know it can only be A or B.

(A) = -1.212317928

(B) = -1.19047619

The answer is A: $-\frac{3}{2} +In\frac{4}{3}$

7 0

3 years ago

What is the total surface area of the rectangular prism?

IRINA_888 [86]

2 sides are 15 x 8 = 240

2 sides are 8 x 6 = 96

2 sides are 15 x 6 = 180

total surface area: 240 + 96 + 180 = 516 square meters

4 0

2 years ago